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A vertex colouring of a graph $G=(V, E)$ with $k$ coulours is a mapping $c: V \rightarrow \{1, \dots , k\}$ such that $c(u) \neq c(v)$ for every $(u, v) \in E$. Consider the following statements:

1. If every vertex in $G$ has degree at most $d$ then $G$ admits a vertex coulouring using $d+1$ colours.
2. Every cycle admits a vertex colouring using $2$ colours
3. Every tree admits a vertex colouring using $2$ colours

Which of the above statements is/are TRUE? Choose from the following options:

1. only i
2. only i and ii
3. only i and iii
4. only ii and iii
5. i, ii, and iii
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1. is true, since in worst case the graph can be complete. So, $d+1$ colours are necessary for graph containing vertices with degree atmost $'d'$ . Example : Consider a complete graph of $4$ vertices ... $K_{4}$

2. is false since cyles with odd no of vertices require $3$ colours.

3. is true, since each level of the tree must be coloured in an alternate fashion. We can do this with two colours. Its a theorem that a tree is $2$ colourable ...

Therefore, option C is correct.

answered by Active (1.5k points)
edited by

in (i) maximum degree is 3 if A,B,C,D are colors so (3+1) colors is used

in (ii) we can see 2 color is used but in (i) ADC is also a cycle but it requires 3 colors so not true for every cycle

in (iii) we can see that A and B two colors are sufficient

So option C is true i and iii is right  option

answered by Loyal (6.7k points)
edited