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1 votes
1 votes
An Internet Service provider (ISP) has the following chunk of CIDR- based IP addresses available 252.224.128.0/22. Now it gives its quarter of addreeses to X, Calculate  the valid allocation of addresses to the X ?

2 Answers

3 votes
3 votes
252.224.128.0/22 has addresses till 252.224.131.255. There are 2^10 hosts in the block.

It is needed that X be given 2^10/4 = 2^8 hosts. So, HID in X = 8 bits. 2 bits will be borrowed to act as SID.

So, possible subnets are:

1. 252.224.1000 0000.0/24 or 252.224.128.0/24

2. 252.224.1000 0001.0/24 or 252.224.129.0/24

3. 252.224.1000 0010.0/24 or 252.224.130.0/24

4. 252.224.1000 0011.0/24 or 252.224.131.0/24

Any one of 252.224.128.0/24 , 252.224.129.0/24, 252.224.130.0/24, 252.224.131.0/24 can be given to X.
1 votes
1 votes
$\underbrace{252.224.100000}_\text{Network ID} \underbrace{00.00000000}_\text{Host ID}$

Now giving 1st quarter of chuck to $X \rightarrow$ $\underbrace{252.224.10000000}_\text{Network ID} .\underbrace{00000000}_\text{Host ID} \rightarrow 252.224.128.0/24$

Then we are left with,

$\underbrace{252.224.10000001}_\text{Network ID} .\underbrace{00000000}_\text{Host ID} \rightarrow 252.224.129.0/24$

$\underbrace{252.224.10000010}_\text{Network ID} .\underbrace{00000000}_\text{Host ID} \rightarrow 252.224.130.0/24$

$\underbrace{252.224.10000011}_\text{Network ID} .\underbrace{00000000}_\text{Host ID} \rightarrow 252.224.131.0/24$

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