The Gateway to Computer Science Excellence
+4 votes
363 views

In the circuit shown below, the propagation delay of each NOT gate is 2 nsec (2 nano sec), then the time period of generated square wave is –

Please somebody explain the approach for this type of qestions

in Digital Logic by
edited by | 363 views

3 Answers

+8 votes
Best answer

When such feedbacking is done which comprises of NOT gates it is known as astable multivibrator and also acts as square wave generator ..

Now the time period of such square wave generator is given by :

2n * tpd  where n is the number of NOT gates involved in feedback circuit and tpd is propogation delay of a NOT gate

So as only 5 NOT gates are involved in feedback circuit so n = 5 here..

Hence time period of given square wave generator    =  2 * n * tpd

                                                                            =  2 * 5 * 2

                                                                            =  20 ns

Hence time period will be 20 ns..

by
selected by
+1 vote
Frequency=1/2*n*tp
where n=odd(only in feedback ckt)

even no of gates doesnot give periodic waveform
by
+1 vote
by
Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true
52,345 questions
60,517 answers
201,937 comments
95,367 users