The virtual memory system uses the demand paging for its implementation. The probability of getting page faults is $0.25$, the normal memory access time is $200$ nanoseconds. If it takes $2$ millseconds to service a page fault, then what is effective memory access time?
@ hem chandra joshi
yes, we consider memory access time .
in this formula Effective Memory Access Time
= (1 - p) * ma + p * page fault service time
we use memory access time as ma .
For those who are confused about which formula to use.