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Suppose the disk drive has $200$ cylinders ( numbered $0$  to $199$). The drive is currently serving the request at cylinder $53$. The previous request was at cylinder $25$. A queue of pending requests in FIFO order is
$98, \ 183, \ 37, \ 122, \ 14, \ 124,\ 65, \ 67$
Starting from the current head position. The total distance traveled by the disk arm in SCAN scheme _______

14    37    53         65          67        98        122      124          183        199

65

67

98

122

124

183

199

37

14

so for  Scan: 53 , 65 , 67 , 98 , 122 , 124 , 183 , 199 , 37 , 14

The total distance: (65-53)+(67-65)+(98-67)+(122-98)+(124-122)+(183-124)+(199-183)+(199-37)+(37-14)= 331 Cylinders

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see my answer carefully and analyse that diagram i draw, it will tell you.

@HRK click below document and check for disk problems

Document

so the request at 25 cylinder is not at all considered?