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A moving arm disk-storage device has the following specifications. Number of tracks per recording surface – $200$ Disk – rotation speed – $2400$ rpm Track storage capacity – $62$, $500$ bits When sector control information takes four Bytes and data area is formatted to $256$ bytes the average number of sectors possible in each track is __________
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Each sector 256 bytes + 4 bytes (control) = 260bytes
Number of sectors = 62500 / (260  * 8)    =  62500 / 2080 = 30.04
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So sir isn't answer supposed to be 31? We fraction of sector extra after 30 sectors?
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 If a track can accommodate 30.04 sectors, does that mean it can accommodate 31 sectors? No.

It's 30 sectors and a little wasted space.

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@JashanArora  

a little wasted space means???

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The exact capacity of the track is such that it can contain 30.048 sectors.
But since we can put only 30 sectors (an integer), and not 30.048 sectors the remaining space which is equivalent to 0.048 sectors is left unused.

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Answer:

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