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Consider the funciton $M$ defined as follows:

$M(n) = \begin{cases} n-10 & \text{ if } n > 100 \\ M(M(n+11)) & \text{ if } n \leq 100 \end{cases}$

Compute the following:

M(101)
asked in Others by Veteran (98.5k points) | 43 views

1 Answer

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M(101) = 101 - 10 = 91         as $n > 100$
answered by Boss (11.4k points)


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