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  1. Split the fd's such that rhs contains single attribute. 
  2. Find the redundant fd's and remove redundant ones. 
  3. Find the redundant attributes on lhs and remove them.like AB->C ,A can be deleted if closure of B contains A
posted Jul 28, 2015 in Databases by Active (2,077 points) | 494 views
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2 Comments

Explanation with proper example would have been noble
2 point you use is false in the example
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