PLEASE CHECK MY UNDERSTANDING:-

**1. Halting Problem:-**

**a) A turing machine halts after running for exactly k steps on any input**

This is DECIDABLE, as the number of steps are finite and we can test it by giving a string whose length is 'k' as input.

**b) A turing machine halts after running for atmost k steps on any input**

This is DECIDABLE, as the number of steps are finite and we can test it by giving a string whose length is 'k' as input.

**c) A turing machine halts after running for atleast k steps on any input**

This is SEMI-DECIDABLE, as we can construct a Turing Machine for this problem and it can loop forever.

**2. State Entry Problem:-
a) A turing machine visits a particular state "q" exactly k times on any input**

We can simulate this problem using Bi-tape or Bi-Track Turing Machine. 1 tape/track can be used to simulate the given turing machine specification and the next track/tape can be used as a counter. We increment the counter whenever we come across that state. But there is chance for looping as that particular state can be visited after very large number of steps. So, this is SEMI-DECIDABLE.

**b) A turing machine visits a particular state "q" atmost k times on any input**

SEMI-DECIDABLE(Same as above)

**c) A turing machine visits a particular state "q" atleast k times on any input**

SEMI-DECIDABLE(Same as above)

**d) A turing machine visits a particular state "q" after exactly k steps on any input**

Number of Steps are finite. So, DECIDABLE.

**e) A turing machine visits a particular state "q" after atmost k steps on any inpur**

Again, Number of Steps are finite. So, DECIDABLE.

**f) A turing machine visits a particular state "q" after atleast k steps on any input**

It may visit "q" after a very large number of steps. So, looping possible. Though we can construct a Turing Machine for this. Hence, SEMI-DECIDABLE.

**g) A turing machine visits exactly n states on any input**

There can be many redundant states and the turing machine might visit only some states for a particular input. For all inputs, it is kinda difficult to decide as we might have to run the turing machine for all possible inputs from the Alphabet set. Though we can simulate the problem statement using a Bi-tape or Bi-Track Turing Machine where the 2nd tape/track acts as the counter. Hence, SEMI-DECIDABLE.

**h) A turing machine visits atmost n states on any input**

SEMI-DECIDABLE(Same as Above).

**i) A turing machine visits atleast n states on any input**

SEMI-DECIDABLE(Same as Above).

**3. Acceptance Problem:-**

**a) A turing machine accepts strings of length exactly "n" **

Basically, Halting Problem reduces to this. Hence, SEMI-DECIDABLE.

**b) A turing machine accepts strings of length atmost "n" **

SEMI-DECIDABLE(Same as Above).

**c) A turing machine accepts strings of length atleast "n" **

SEMI-DECIDABLE(Same as Above).

**4. PROBLEM RELATED TO CONTROL OF TURING MACHINE:-
a) The control of a turing machine moves right exactly n times on any input**

If it was 1 time, we can easily decide. Also if it was for 1 particular string, we can decide. But for all strings in the Language, it is kinda difficult to decide as we might have to run the turing machine for all possible inputs from the Alphabet set. Though we can simulate the problem statement using a Bi-tape or Bi-Track Turing Machine where the 2nd tape/track acts as the counter. Hence, SEMI-DECIDABLE.

**b) The control of a turing machine moves right atmost n times on any input**

SEMI-DECIDABLE(same as above).

**c) The control of a turing machine moves right atleast n times on any input**

SEMI-DECIDABLE(same as above).

**5. PROBLEM RELATED TO REPLACEMENT OF CHARACTER IN TURING MACHINE:-
a) A turing machine replaces the characters on the tape exactly n times on any input **

If it was for 1 particular string, we can decide. But for all strings in the Language, it is kinda difficult to decide as we might have to run the turing machine for all possible inputs from the Alphabet set. Though we can simulate the problem statement using a Bi-tape or Bi-Track Turing Machine where the 2nd tape/track acts as the counter. Hence, SEMI-DECIDABLE.

**b) A turing machine replaces the characters on the tape atleast n times on any input**

SEMI-DECIDABLE(same as above).

**c) A turing machine replaces the characters on the tape atmost n times on any input**

SEMI-DECIDABLE(same as above).

@Balaji

https://www.seas.upenn.edu/~cit596/notes/dave/halting6.html

this is state entry problem which has a input w

And also yes state entry problem and halting problem both undecidable

but in ur question, where is any input?