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Recent posts tagged happy-birthday

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(C) is the answer. Because of AB $\to$ C and C $\to$ A, we cannot have A, B and C together in any BCNF relation- in relation ABC, C is not a super key and C$\to$ A exists violating BCNF condition. So, we cannot preserve AB $\to$ C dependency in any decomposition of ABCD. ... and B the respective keys For (B) we can have AB, BC, CD, A, B and C the respective keys For (D) we can have ABCD, A is key
posted Nov 6, 2018 in Others Devshree Dubey 1,250 views
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