Recent questions and answers in Digital Signal Processing

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1

NIELIT 2017 July Scientist B (CS) - Section B: 31
At a room temperature of $300K$, calculate the thermal noise generated by two resistors of $10K\Omega$ and $20K\Omega$ when the bandwidth is $10KHz$. $1.2868\times10^{-6}V, 1.819\times10^{-6}V$ $6.08\times10^{-6}V, 15.77\times10^{-6}V$ $16.66\times10^{-6}V, 2.356\times10^{-6}V$ $1.66\times10^{-6}V, 0.23\times10^{-6}V$

At a room temperature of $300K$, calculate the thermal noise generated by two resistors of $10K\Omega$ and $20K\Omega$ when the bandwidth is $10KHz$. $1.2868\times10^{-6}V, 1.819\times10^{-6}V$ $6.08\times10^{-6}V, 15.77\times10^{-6}V$ $16.66\times10^{-6}V, 2.356\times10^{-6}V$ $1.66\times10^{-6}V, 0.23\times10^{-6}V$

answered Oct 4, 2020 in Digital Signal Processing Madhav 194 views

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3 answers

2

NIELIT 2017 DEC Scientific Assistant A - Section B: 8
Microprocessors are used in which generation of computers? I – st Generation II – nd Generation III – rd Generation IV – th Generation

Microprocessors are used in which generation of computers? I – st Generation II – nd Generation III – rd Generation IV – th Generation

answered Sep 20, 2020 in Digital Signal Processing Himanshu Kumar Gupta 213 views

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1 answer

3

NIELIT 2017 OCT Scientific Assistant A (CS) - Section D: 2
An ideal op-amp is an ideal voltage controlled current source voltage controlled voltage source current controlled current source current controlled voltage source

An ideal op-amp is an ideal voltage controlled current source voltage controlled voltage source current controlled current source current controlled voltage source

answered Sep 20, 2020 in Digital Signal Processing Himanshu Kumar Gupta 83 views

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4

NIELIT 2017 OCT Scientific Assistant A (IT) - Section D: 1
Twelve $1\;\Omega$ resistances are used as edges to from a cube. The resistance between two diagonally opposite corners of the cube is $\frac{5}{6}\;\Omega$ $\frac{1}{6}\;\Omega$ $\frac{6}{5}\;\Omega$ $\frac{3}{2}\;\Omega$

Twelve $1\;\Omega$ resistances are used as edges to from a cube. The resistance between two diagonally opposite corners of the cube is $\frac{5}{6}\;\Omega$ $\frac{1}{6}\;\Omega$ $\frac{6}{5}\;\Omega$ $\frac{3}{2}\;\Omega$

asked Aug 28, 2020 in Digital Signal Processing Lakshman Patel RJIT 84 views

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5

NIELIT 2017 OCT Scientific Assistant A (IT) - Section D: 11
In MOSFET fabrication, the channel; length is defined during the process of Isolation oxide growth Channel stop implantation Poly-silicon gate patterning Lithography step leading to the contact pad

In MOSFET fabrication, the channel; length is defined during the process of Isolation oxide growth Channel stop implantation Poly-silicon gate patterning Lithography step leading to the contact pad

asked Aug 28, 2020 in Digital Signal Processing Lakshman Patel RJIT 54 views

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0 answers

6

NIELIT 2017 OCT Scientific Assistant A (CS) - Section D: 1
Twelve $1\;\Omega$ resistances are used as edges to from a cube. The resistance between two diagonally opposite corners of the cube is $\frac{5}{6}\;\Omega$ $\frac{1}{6}\;\Omega$ $\frac{6}{5}\;\Omega$ $\frac{3}{2}\;\Omega$

Twelve $1\;\Omega$ resistances are used as edges to from a cube. The resistance between two diagonally opposite corners of the cube is $\frac{5}{6}\;\Omega$ $\frac{1}{6}\;\Omega$ $\frac{6}{5}\;\Omega$ $\frac{3}{2}\;\Omega$

asked Aug 28, 2020 in Digital Signal Processing Lakshman Patel RJIT 66 views

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0 answers

7

NIELIT 2017 OCT Scientific Assistant A (CS) - Section D: 3
The final value theorem is used to find the Steady state value of the system output Initial value of the system output Transient behavior of the system output None of these

The final value theorem is used to find the Steady state value of the system output Initial value of the system output Transient behavior of the system output None of these

asked Aug 28, 2020 in Digital Signal Processing Lakshman Patel RJIT 68 views

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0 answers

8

NIELIT 2017 OCT Scientific Assistant A (CS) - Section D: 4
For the discrete signal $x[n] = a^{n}u[n],a>0$ the $z$-transform is $\frac{(z+a)}{z}$ $\frac{(z-a)}{z}$ $\frac{z}{(z-a)}$ $\frac{z}{(z+a)}$

For the discrete signal $x[n] = a^{n}u[n],a>0$ the $z$-transform is $\frac{(z+a)}{z}$ $\frac{(z-a)}{z}$ $\frac{z}{(z-a)}$ $\frac{z}{(z+a)}$

asked Aug 28, 2020 in Digital Signal Processing Lakshman Patel RJIT 71 views

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0 answers

9

NIELIT 2017 OCT Scientific Assistant A (CS) - Section D: 5
For a periodic signal $v(t) = 30\sin 100t + 10\cos 300t + 6\sin(500t + \frac{\pi}{4}),$ the fundamental frequency in rad/s $100$ $300$ $500$ None of these

For a periodic signal $v(t) = 30\sin 100t + 10\cos 300t + 6\sin(500t + \frac{\pi}{4}),$ the fundamental frequency in rad/s $100$ $300$ $500$ None of these

asked Aug 28, 2020 in Digital Signal Processing Lakshman Patel RJIT 70 views

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0 answers

10

NIELIT 2017 OCT Scientific Assistant A (CS) - Section D: 7
If the number of bits per sample in a PCM system is increased from a $n$ to $n+1,$ the improvement in signal to quantization nose ratio will be $3\;dB$ $6\;dB$ $2n\;dB$ $n\;dB$

If the number of bits per sample in a PCM system is increased from a $n$ to $n+1,$ the improvement in signal to quantization nose ratio will be $3\;dB$ $6\;dB$ $2n\;dB$ $n\;dB$

asked Aug 28, 2020 in Digital Signal Processing Lakshman Patel RJIT 59 views

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0 answers

11

NIELIT 2017 OCT Scientific Assistant A (CS) - Section D: 8
A carrier $Ac\cos(\omega c)t$ is frequency modulated by a signal $Em\cos(\omega m)t.$ The modulation index is $mf.$ The expression for the resulting FM signal is $Ac\cos [\omega ct + mf\sin(\omega m)t]$ ... $Ac\cos [\omega ct + 2\pi mf Em \cos(\omega m)t/\omega m]$

A carrier $Ac\cos(\omega c)t$ is frequency modulated by a signal $Em\cos(\omega m)t.$ The modulation index is $mf.$ The expression for the resulting FM signal is $Ac\cos [\omega ct + mf\sin(\omega m)t]$ $Ac\cos [\omega ct + mf\cos(\omega m)t]$ $Ac\cos [\omega ct + \pi mf\sin \omega m t]$ $Ac\cos [\omega ct + 2\pi mf Em \cos(\omega m)t/\omega m]$

asked Aug 28, 2020 in Digital Signal Processing Lakshman Patel RJIT 57 views

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0 answers

12

NIELIT 2017 OCT Scientific Assistant A (CS) - Section D: 11
In MOSFET fabrication, the channel; length is defined during the process of Isolation oxide growth Channel stop implantation Poly-silicon gate patterning Lithography step leading to the contact pad

In MOSFET fabrication, the channel; length is defined during the process of Isolation oxide growth Channel stop implantation Poly-silicon gate patterning Lithography step leading to the contact pad

asked Aug 28, 2020 in Digital Signal Processing Lakshman Patel RJIT 54 views

0 votes

0 answers

13

NIELIT 2017 OCT Scientific Assistant A (CS) - Section D: 12
The open-loop transfer function of a feedback control system is $G(s)\cdot H(s) = 1/(s+1)^{3}.$ The gain margin of the system is $2$ $4$ $8$ $16$

The open-loop transfer function of a feedback control system is $G(s)\cdot H(s) = 1/(s+1)^{3}.$ The gain margin of the system is $2$ $4$ $8$ $16$

asked Aug 28, 2020 in Digital Signal Processing Lakshman Patel RJIT 66 views

0 votes

1 answer

14

NIELIT 2016 DEC Scientist B (CS) - Section B: 60
The sequence of operation in which PCM is done is Sampling, quantizing, encoding Quantizing, sampling, encoding Quantizing, encoding, sampling None of the above

The sequence of operation in which PCM is done is Sampling, quantizing, encoding Quantizing, sampling, encoding Quantizing, encoding, sampling None of the above

answered Jun 10, 2020 in Digital Signal Processing Ollie 986 views

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1 answer

15

NIELIT 2016 DEC Scientist B (CS) - Section B: 41
The IETF standard documents are called: RFC RCF ID none of the above

The IETF standard documents are called: RFC RCF ID none of the above

answered Jun 10, 2020 in Digital Signal Processing Ollie 99 views

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1 answer

16

NIELIT 2016 DEC Scientist B (CS) - Section B: 17
$T1$ carrier system is used: For delta modulation Industrial noise For frequency modulated signals None of the above

$T1$ carrier system is used: For delta modulation Industrial noise For frequency modulated signals None of the above

answered May 25, 2020 in Digital Signal Processing Mohit Kumar 6 172 views

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1 answer

17

NIELIT 2016 MAR Scientist C - Section C: 48
In a microprocessor, WAIT states are used to make the processor wait during a DMA operation make the processor wait during a power interrupt processing make the processor wait during a power shutdown interface slow peripherals to the processor

In a microprocessor, WAIT states are used to make the processor wait during a DMA operation make the processor wait during a power interrupt processing make the processor wait during a power shutdown interface slow peripherals to the processor

answered May 19, 2020 in Digital Signal Processing Mohit Kumar 6 138 views

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1 answer

18

NIELIT 2016 DEC Scientist B (CS) - Section B: 25
A low pass filter is Passes the frequencies lower than the specified cut off frequency Used to recover signal from sampled signal Rejects higher frequencies All of the above

A low pass filter is Passes the frequencies lower than the specified cut off frequency Used to recover signal from sampled signal Rejects higher frequencies All of the above

answered Apr 25, 2020 in Digital Signal Processing Sabirazain 242 views

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1 answer

19

NIELIT 2016 MAR Scientist C - Section C: 61
Microprogramming is a technique for writing small programs effectively programming output/input routines programming the microprocessors programming the control steps of a computer

Microprogramming is a technique for writing small programs effectively programming output/input routines programming the microprocessors programming the control steps of a computer

answered Apr 4, 2020 in Digital Signal Processing Vipin Tiwari 105 views

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0 answers

20

NIELIT 2016 MAR Scientist C - Section C: 42
A stable multivibrator are used as comparator circuit squaring circuit frequency to voltage converter voltage to frequency converter

A stable multivibrator are used as comparator circuit squaring circuit frequency to voltage converter voltage to frequency converter

asked Apr 2, 2020 in Digital Signal Processing Lakshman Patel RJIT 69 views

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0 answers

21

NIELIT 2016 MAR Scientist C - Section C: 43
The astable multivibrator has two quasi stable states two stable states one stable and one quasi-stable state none of these

The astable multivibrator has two quasi stable states two stable states one stable and one quasi-stable state none of these

asked Apr 2, 2020 in Digital Signal Processing Lakshman Patel RJIT 60 views

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0 answers

22

NIELIT 2017 OCT Scientific Assistant A (CS) - Section B: 27
At $100\%$ modulation, the power in each sideband is _______ of that of carrier. $50\%$ $40\%$ $60\%$ $25\%$

At $100\%$ modulation, the power in each sideband is _______ of that of carrier. $50\%$ $40\%$ $60\%$ $25\%$

asked Apr 1, 2020 in Digital Signal Processing Lakshman Patel RJIT 70 views

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0 answers

23

KPGCET-CSE-2019-49
The communication network comprises number of base stations. The scope of each base station covers the circular area. To avoid the overlapping and gaping of areas, the scope of each base station is accounted by Rectangle Pentagon Hexagon Octagon

The communication network comprises number of base stations. The scope of each base station covers the circular area. To avoid the overlapping and gaping of areas, the scope of each base station is accounted by Rectangle Pentagon Hexagon Octagon

asked Aug 4, 2019 in Digital Signal Processing gatecse 34 views

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0 answers

24

KPGCET-CSE-2019-51
In a communicative network, though the scope of base station is circular area, the network scope is represented by______ shape, as it is nearest to the circular area. triangular rectangular pentagonal hexagonal.

In a communicative network, though the scope of base station is circular area, the network scope is represented by______ shape, as it is nearest to the circular area. triangular rectangular pentagonal hexagonal.

asked Aug 4, 2019 in Digital Signal Processing gatecse 23 views

2 votes

3 answers

25

UGCNET-June2016-III: 58
Consider a discrete memoryless channel and assume that H(x) is the amount of information per symbol at the input of the channel; H(y) is the amount of information per symbol at the output of the channel. H(x $\mid$ y) is the amount of uncertainty remaining on x knowing y; and I(x;y)is the ... (y $\mid$ x)]; p(x) max [H(x)-H(x $\mid$ y)]; p(x) max H(x $\mid$y); p(x)

Consider a discrete memoryless channel and assume that H(x) is the amount of information per symbol at the input of the channel; H(y) is the amount of information per symbol at the output of the channel. H(x $\mid$ y) is the amount of uncertainty remaining on x knowing y; and I(x;y)is the information transmission. ... -H(y $\mid$ x)]; p(x) max [H(x)-H(x $\mid$ y)]; p(x) max H(x $\mid$y); p(x)

answered May 3, 2019 in Digital Signal Processing Adnan Ashraf 967 views

2 votes

1 answer

26

UGCNET-Dec2014-III: 66
A Butterworth lowpass filter of order $n$, with a cutoff frequency at distance $D_{0}$ from the origin, has the transfer function $H(u, v)$ given by $\frac{1}{1+\left[\frac{D(u, v)}{D_{0}}\right]^{2n}}$ $\frac{1}{1+\left[\frac{D(u, v)}{D_{0}}\right]^{n}}$ $\frac{1}{1+\left[\frac{D_{0}}{D(u, v)}\right]^{2n}}$ $\frac{1}{1+\left[\frac{D_{0}}{D(u, v)}\right]^{n}}$

A Butterworth lowpass filter of order $n$, with a cutoff frequency at distance $D_{0}$ from the origin, has the transfer function $H(u, v)$ given by $\frac{1}{1+\left[\frac{D(u, v)}{D_{0}}\right]^{2n}}$ $\frac{1}{1+\left[\frac{D(u, v)}{D_{0}}\right]^{n}}$ $\frac{1}{1+\left[\frac{D_{0}}{D(u, v)}\right]^{2n}}$ $\frac{1}{1+\left[\frac{D_{0}}{D(u, v)}\right]^{n}}$

answered Jan 5, 2017 in Digital Signal Processing Sanjay Sharma 661 views

3 votes

1 answer

27

UGCNET-Dec2014-III: 64
Given two spatial masks $S_{1}= \begin{bmatrix} 0&1&0 \\ 1&-4&0 \\ 0&1&0 \end{bmatrix}$ $S_{2} = \begin{bmatrix} 1&1&1 \\ 1&-8&1 \\ 1&1&1 \end{bmatrix}$ The Laplacian of an image at all points $(x, y)$ can be ... of the following can be used as the spatial mask ? only $S_{1}$ only $S_{2}$ Both $S_{1}$ and $S_{2}$ None of these

Given two spatial masks $S_{1}= \begin{bmatrix} 0&1&0 \\ 1&-4&0 \\ 0&1&0 \end{bmatrix}$ $S_{2} = \begin{bmatrix} 1&1&1 \\ 1&-8&1 \\ 1&1&1 \end{bmatrix}$ The Laplacian of an image at all points $(x, y)$ can be implemented by convolving the image with spatial mask. Which of the following can be used as the spatial mask ? only $S_{1}$ only $S_{2}$ Both $S_{1}$ and $S_{2}$ None of these

answered Dec 23, 2016 in Digital Signal Processing Sanjay Sharma 1.3k views

–2 votes

0 answers

28

3sin(200rt) is amplitude modulated with 600
3sin(200rt) is amplitude modulated with 600s(6000rt) Find the spectral response and expression of the AM signal generated

3sin(200rt) is amplitude modulated with 600s(6000rt) Find the spectral response and expression of the AM signal generated

asked Nov 28, 2016 in Digital Signal Processing rahuldb 176 views

1 vote

1 answer

29

UGCNET-Dec2015-III: 51
Blind image disconvolution is Combination of blur identification and image restoration Combination of segmentation and classification Combination of blur and non-blur image None of the above

Blind image disconvolution is Combination of blur identification and image restoration Combination of segmentation and classification Combination of blur and non-blur image None of the above

answered Aug 11, 2016 in Digital Signal Processing Sanjay Sharma 828 views

3 votes

1 answer

30

UGCNET-June2012-II: 18
Page Shift Keying (PSK) Method is used to modulate digital signal at 9600 bps using 16 level. Find the line signals and speed (i.e., modulation rate) 2400 bauds 1200 bauds 4800 bauds 9600 bauds

Page Shift Keying (PSK) Method is used to modulate digital signal at 9600 bps using 16 level. Find the line signals and speed (i.e., modulation rate) 2400 bauds 1200 bauds 4800 bauds 9600 bauds

answered Jul 5, 2016 in Digital Signal Processing Sanjay Sharma 2.3k views

0 votes

1 answer

31

net12

answered May 6, 2016 in Digital Signal Processing rude 98 views

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content	content:apple
exclude	-tag:apple
force match	+apple
views	views:100
score	score:10
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