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Concept of layering.OSI and TCP/IP Protocol Stacks; Basics of packet, circuit and virtual circuit-switching; Data link layer: framing, error detection, Medium Access Control, Ethernet bridging; Routing protocols: shortest path, flooding, distance vector and link state routing; Fragmentation and IP addressing, IPv4, CIDR notation, Basics of IP support protocols (ARP, DHCP, ICMP), Network Address Translation (NAT); Transport layer: flow control and congestion control, UDP, TCP, sockets; Application layer protocols: DNS, SMTP, HTTP, FTP, Email.

.$$\scriptsize{\overset{{\large{\textbf{Mark Distribution in Previous GATE}}}}{\begin{array}{|c|c|c|c|c|c|c|c|}\hline
\textbf{Year}& \textbf{2022} & \textbf{2021-1}&\textbf{2021-2}&\textbf{2020}&\textbf{2019}&\textbf{2018}&\textbf{2017-1}&\textbf{2017-2}&\textbf{2016-1}&\textbf{2016-2}&\textbf{Minimum}&\textbf{Average}&\textbf{Maximum}
\\\hline\textbf{1 Mark Count} & 2 &1&1&2&1&3&2&3&2&3&1&2&3
\\\hline\textbf{2 Marks Count} & 4 &4&3&2&4&2&3&1&4&3&1&3&4
\\\hline\textbf{Total Marks} & 10 &9&7&6&9&7&8&5&10&9&\bf{5}&\bf{8}&\bf{10}\\\hline
\end{array}}}$$

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Hot questions in Computer Networks

27 votes
4 answers
151
GATE CSE 2007 | Question: 68, ISRO2016-73
The message $11001001$ is to be transmitted using the CRC polynomial $x^3 +1$ to protect it from errors. The message that should be transmitted is: $11001001000$ $11001001011$ $11001010$ $110010010011$
The message $11001001$ is to be transmitted using the CRC polynomial $x^3 +1$ to protect it from errors. The message that should be transmitted is:$11001001000$$110010010...
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0 votes
1 answer
153
ISRO 2024
Which of the following is the cause of Ping of death issue related to ICMP packets? Buffer overflow Divide by ZERO Missing input sanitization Privilege escalation
Which of the following is the cause of Ping of death issue related to ICMP packets?Buffer overflowDivide by ZEROMissing input sanitizationPrivilege escalation
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0 votes
0 answers
155
#selfdoubt
In CRC, if the dataword is 5 bits and the codeword is 8 bits, how many 0s need to be added to the dataword to make the dividend? What is the size of the remainder? What is the size of the divisor?
In CRC, if the dataword is 5 bits and the codeword is 8 bits, how many 0s need to be added to the dataword to make the dividend? What is the size of the remainder? What i...
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2 votes
0 answers
161
madeeasy ots
In first option one bit error to merge two consecutive frames into one – I cannot understand this. B should be 2^k/2-1 for selective reject. It should be false . Right??
In first option one bit error to merge two consecutive frames into one – I cannot understand this. B should be 2^k/2-1 for selective reject. It should be false . Right...
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0 votes
0 answers
165
Self Doubt Topology
Which topology covers security robust and eliminating traffic factors? a. Mesh b. Ring c. Star d. bus i am confused with mesh or star or bus option. please give clarification on this as well
Which topology covers security robust and eliminating traffic factors?a. Meshb. Ringc. Stard. bus i am confused with mesh or star or bus option. please give clarificati...
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0 votes
1 answer
166
self doubt
In fragmentation, if any fragment gets lost then in which case whole packet will be sent again? and in which case only that fragment will be sent again?
In fragmentation, if any fragment gets lostthen in which case whole packet will be sent again?and in which case only that fragment will be sent again?
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0 votes
1 answer
167
#TTL#Computer Network
if between sender and receiver, there are 3 routers and TTL value initialized by the sender 4 then receiver will accept the packet ?
if between sender and receiver, there are 3 routers and TTL value initialized by the sender 4 then receiver will accept the packet ?
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1 votes
2 answers
170
#ACE acedmy test series
In a host size for PDU of network layer is 17076 bytes, MTU size for that network is 200 bytes and IPv4 header size is 20 bytes .find number of IP fragments
In a host size for PDU of network layer is 17076 bytes, MTU size for that network is 200 bytes and IPv4 header size is 20 bytes .find number of IP fragments
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