GATE CSE 2008 | Question: 8
Given $f_1$, $f_3$ and $f$ in canonical sum of products form (in decimal) for the circuit $f_1 = \Sigma m(4, 5, 6, 7, 8)$ $f_3 = \Sigma m(1, 6, 15)$ $f = \Sigma m(1, 6, 8, 15)$ then $f_2$ is $\Sigma m(4, 6)$ $\Sigma m(4, 8)$ $\Sigma m(6, 8)$ $\Sigma m(4, 6, 8)$
Given $f_1$, $f_3$ and $f$ in canonical sum of products form (in decimal) for the circuit$f_1 = \Sigma m(4, 5, 6, 7, 8)$$f_3 = \Sigma m(1, 6, 15)$$f = \Sigma m(1, 6, 8, 1...