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Syllabus: Limits, Continuity, and Differentiability, Maxima and minima, Mean value theorem, Integration.

$$\scriptsize{\overset{{\large{\textbf{Mark Distribution in Previous GATE}}}}{\begin{array}{|c|c|c|c|c|c|c|c|}\hline
\textbf{Year}&\textbf{2022} & \textbf{2021-1}&\textbf{2021-2}&\textbf{2020}&\textbf{2019}&\textbf{2018}&\textbf{2017-1}&\textbf{2017-2}&\textbf{2016-1}&\textbf{2016-2}&\textbf{Minimum}&\textbf{Average}&\textbf{Maximum}
\\\hline\textbf{1 Mark Count} & 1 &1&1&1&1&1&0&1&1&1&0&0.9&1
\\\hline\textbf{2 Marks Count} & 0 &0&0&0&0&0&1&0&0&0&0&0.1&1
\\\hline\textbf{Total Marks} & 1 &1&1&1&1&1&2&1&1&1&\bf{1}&\bf{1.1}&\bf{2}\\\hline
\end{array}}}$$

4 votes
2 answers
91
Consider the following expression.$$\displaystyle \lim_{x\rightarrow-3}\frac{\sqrt{2x+22}-4}{x+3}$$The value of the above expression (rounded to 2 decimal places) is ____...
0 votes
1 answer
93
0 votes
0 answers
94
Does there exist a differentiable function f : [0, 2] → R satisfying f(0) = −1, f(2) = 4 and f’(x) ≤ 2 for all x ∈ [0, 2]?
0 votes
1 answer
95
22 votes
5 answers
96
3 votes
2 answers
97
1 votes
0 answers
98
Let f(x-y) = $\frac{f(x)}{f(y)}$ for all x,y $\epsilon$ R and f’(0) = p, f’(5) = q. Then the value of f’(-5) is q-q$\frac{p}{q}$$\frac{p^2}{q}$
15 votes
3 answers
100
$\displaystyle \lim_{x \to 0} \frac{x(e^x - 1) + 2(\cos x -1)}{x(1 - \cos x)}$ is __________
0 votes
1 answer
101
Options Given were:(pi)/2pi-(pi)none
1 votes
1 answer
102
Dear Friends can any body tell me limit exists at 1 or not? as According to me the limit exists at 1 as both gives -1 at 1 but in madeeasy it’s given that the limit doe...
0 votes
1 answer
103
f(x) = [$ tan ^2$ x] ( [ ] stands for greatest integer function)a) f(x) continuous at x = 0b) limit f(x) does not exist as x tend to 0c) f '(0) = 1d) f(x) not derivable ...
1 votes
2 answers
104
1 votes
2 answers
105
Evaluate the limit:$$ \lim_{x \to -3} \frac{\sqrt{2x+22}-4}{x+3}$$$\frac{1}{2}$$\frac{1}{4}$$\frac{1}{8}$$\frac{1}{16}$
0 votes
2 answers
106
Calculus looks difficult for me. Any resources to learn calculus for GATE
0 votes
0 answers
107
What is the correct procedure to solve this limit ?
1 votes
2 answers
108
4 votes
1 answer
109
It should be 1 and 3 ?? please correct me if I'm wrong.
1 votes
2 answers
110
$\displaystyle \lim_{x \rightarrow 0}\frac{1}{x^{6}} \displaystyle \int_{0}^{x^{2}}\frac{t^{2}dt}{t^{6}+1}=$?$1/4$$1/3$$1/2$$1$