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Syllabus: Limits, Continuity, and Differentiability, Maxima and minima, Mean value theorem, Integration.

$$\scriptsize{\overset{{\large{\textbf{Mark Distribution in Previous GATE}}}}{\begin{array}{|c|c|c|c|c|c|c|c|}\hline
\textbf{Year}&\textbf{2022} & \textbf{2021-1}&\textbf{2021-2}&\textbf{2020}&\textbf{2019}&\textbf{2018}&\textbf{2017-1}&\textbf{2017-2}&\textbf{2016-1}&\textbf{2016-2}&\textbf{Minimum}&\textbf{Average}&\textbf{Maximum}
\\\hline\textbf{1 Mark Count} & 1 &1&1&1&1&1&0&1&1&1&0&0.9&1
\\\hline\textbf{2 Marks Count} & 0 &0&0&0&0&0&1&0&0&0&0&0.1&1
\\\hline\textbf{Total Marks} & 1 &1&1&1&1&1&2&1&1&1&\bf{1}&\bf{1.1}&\bf{2}\\\hline
\end{array}}}$$

Recent questions in Calculus

4 votes
1 answer
91
2 votes
1 answer
96
If $\displaystyle \lim_{x \to 0}\sin{(mx)}\cot{\left (\frac{x}{\sqrt 3}\right)} = 2$ then $m = $ _________ (rounded off up to $2$ decimal places)
2 votes
1 answer
97
If $f(x) = \dfrac{1}{4x^2+2x+1}$ then its maximum value is$0.75$$1.33$$0.25$It does not have a maximum value
1 votes
1 answer
98
The minimum value of the function $$f(x) = \frac{x^3}{3} - x$$ occurs at$x = 1$$x =-1$$x = 0$$ x = \frac{1}{\sqrt{3}}$
1 votes
2 answers
99
1 votes
1 answer
100
2 votes
1 answer
102
1 votes
1 answer
103
1 votes
1 answer
104
Find the 'c' of Rolle's mean value theorem for $f(x) = x^3 - 4x \in [-2,2].$$\frac{2}{\sqrt{3}}$$-\frac{2}{\sqrt{3}}$$\pm \frac{2}{\sqrt{3}}$None of the above
2 votes
1 answer
105
Compute the value of $$\int_{0}^{\frac{\pi}{2}}\frac{\tan^7 x}{\cot^7x + \tan^7x}dx$$$\pi$$\frac{\pi}{4}$$1$$\frac{\pi}{2}$
1 votes
1 answer
106
Which of the following function(s) is/are continuous at $x = 3?$ (Mark all the appropriate choices)$f(x) = \left\{\begin{matrix}2; & \text{when } x = 3 \\x-1; & \text{whe...
2 votes
1 answer
107
Consider the following definite integral $$I =\int_{0}^{1}\frac{(\sin^{-1} x)^2}{\sqrt{1-x^2}}dx$$ The value of the integral is$\frac{\pi^3}{24}$$\frac{\pi^3}{12}$$\frac{...
4 votes
1 answer
108
What is the value of the integration $$I =\int_{0}^{\frac{\pi}{2}}\log(\sin x)\;dx$$0$\frac{-\pi}{2}\log 2$$-\pi \log 2$$\log 2$
2 votes
1 answer
109
The value of the integral $$I =\int_{-1}^{2}\left(1 + \mid x \mid \right)dx$$ $=$ _________ (rounded up to $1$ decimal place)
3 votes
1 answer
110
The value of the integral $$I =\int_{-\infty }^{\infty}\frac{dx}{1+x^2}$$$-\pi$$-\frac{\pi}{2}$$\frac{\pi}{2}$$\pi$