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Syllabus: Propositional and first order logic.

$$\scriptsize{\overset{{\large{\textbf{Mark Distribution in Previous GATE}}}}{\begin{array}{|c|c|c|c|c|c|c|c|}\hline
\textbf{Year}& \textbf{2022}& \textbf{2021-1}&\textbf{2021-2}&\textbf{2020}&\textbf{2019}&\textbf{2018}&\textbf{2017-1}&\textbf{2017-2}&\textbf{2016-1}&\textbf{2016-2}&\textbf{Minimum}&\textbf{Average}&\textbf{Maximum}
\\\hline\textbf{1 Mark Count}& 0 & 1&1&0&0&0&2&1&1&1&0&0.7&2
\\\hline\textbf{2 Marks Count}&0 & 0&0&1&1&1&1&0&0&1&0&0.5&1
\\\hline\textbf{Total Marks}& 0 & 1&1&2&2&2&4&1&1&3&\bf{0}&\bf{1.7}&\bf{4}\\\hline
\end{array}}}$$

Highest voted questions in Mathematical Logic

26 votes
5 answers
63
24 votes
4 answers
66
Which of the following is/are a tautology?$a \vee b \to b \wedge c$$a \wedge b \to b \vee c$$a \vee b \to \left(b \to c \right)$$a \to b \to \left(b \to c \right)$
23 votes
9 answers
69
23 votes
4 answers
70
The proposition $p \wedge (\sim p \vee q)$ is:a tautologylogically equivalent to $p \wedge q$logically equivalent to $p \vee q$a contradictionnone of the above
22 votes
3 answers
71
Let $p$ and $q$ be propositions. Using only the Truth Table, decide whether $p \Longleftrightarrow q$ does not imply $p \to \lnot q$is True or False.
21 votes
3 answers
73
Obtain the principal (canonical) conjunctive normal form of the propositional formula $$(p \wedge q) \vee (\neg q \wedge r)$$ where $\wedge$ is logical and, $\vee$ is inc...
18 votes
7 answers
76