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Regular expressions and finite automata, Context-free grammars and push-down automata, Regular and context-free languages, Pumping lemma, Turing machines and undecidability.

$$\scriptsize{\overset{{\large{\textbf{Mark Distribution in Previous GATE}}}}{\begin{array}{|c|c|c|c|c|c|c|c|}\hline
\textbf{Year}& \textbf{2022} & \textbf{2021-1}&\textbf{2021-2}&\textbf{2020}&\textbf{2019}&\textbf{2018}&\textbf{2017-1}&\textbf{2017-2}&\textbf{2016-1}&\textbf{2016-2}&\textbf{Minimum}&\textbf{Average}&\textbf{Maximum}
\\\hline\textbf{1 Mark Count} & 2 &2&3&3&2&2&2&3&3&3&2&2.5&3
\\\hline\textbf{2 Marks Count} & 3 &3&4&3&3&3&5&3&3&3&3&3.3&5
\\\hline\textbf{Total Marks} & 8 &8&11&9&8&8&12&9&9&9&\bf{8}&\bf{9.1}&\bf{12}\\\hline
\end{array}}}$$

Recent questions in Theory of Computation

1 votes
1 answer
3181
S→0A|1B|0|1 A→0S|1D|1B→0C|1S|0C→1D|0S|1D→0C|1S|0 The number of states and final states in min DFA are -?
3 votes
2 answers
3183
2 votes
0 answers
3184
How L1 is regular...? Explain...
1 votes
1 answer
3185
Which of the following are decidable?1. Complement of a regular language is infinite.2. Whether a given CFG is regular
2 votes
1 answer
3186
Given a finite automata M, is it the minimum state FA accepting L(M)is this problem decidable, if yes then why?
3 votes
0 answers
3187
1 votes
2 answers
3188
Are the languages produced (a+b)* and (a*b*)* same?
1 votes
0 answers
3190
HOW is L2 CFL?
2 votes
1 answer
3191
How is L3 regular?
1 votes
1 answer
3194
I can use 4 state dfa for no. of a should be divisible by 4 then minimum = 4 , or we have to construct dfa with 8 states ??
3 votes
1 answer
3195
How many states in dfa of X= { (a+b)* where no of a is divisible by 4 and 8}
1 votes
0 answers
3196
A is a P-problem B is a NP problem and L= A intersection B , then L is1.always P2.L is NP but may not be P
2 votes
1 answer
3198
Which of the following functions are Turing Machine computable?$1) \ n \times (n-1) \times (n-2) ......1$$2)\{log_2n\}$$3)\Large2^{2^n}$
2 votes
1 answer
3199
2 votes
1 answer
3200
$L_1=\{a^nb^nc^n\ |n>=0\}$$L_2=\{a^{2n}b^{2n}c^{2n}\ |n>=0\}$$L_3=\{ a^{2n}b^{2n}c^n\ |n>=0\}$Options :$1)\ L_2 \subseteq L_1 \&L_2 \subseteq L_3 $$2)\ L_2 \subseteq L_1 ...