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Search results for rice-theorem
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Rice's Theorem
Example# 3 from Part-1 Rice's Theorem from https://gatecse.in/rices-theorem/ states as follows (3) L(M) is recognized by a TM having even number of states Sol: This is a trivial property. This set equals the set of recursively enumerable languages. ... then? Can someone give me an example for which TYES and TNO cannot be found and let me know if my approach is correct ?
Example# 3 from Part-1 Rice's Theorem from https://gatecse.in/rices-theorem/ states as follows (3) L(M) is recognized by a TM having even number of statesSol: This is a t...
Salazar
758
views
Salazar
asked
Oct 28, 2017
Theory of Computation
decidability
rice-theorem
theory-of-computation
self-doubt
+
–
1
votes
1
answer
2
Turing Machine Rice's Theorem
L = {M|M is a TM that accepts all even numbers} For the above language i can have Tyes machine which has all even numbers.And Tno as machine whose language is empty.So i can say it is undecidable. But to show it is Not RE. What ... am assuming here that the property of the language as "Only all even numbers",i guess the same has been given in the question.
L = {M|M is a TM that accepts all even numbers}For the above language i can have Tyes machine which has all even numbers.And Tno as machine whose language is empty.So i c...
rahul sharma 5
1.3k
views
rahul sharma 5
asked
Aug 5, 2017
Theory of Computation
decidability
rice-theorem
theory-of-computation
turing-machine
self-doubt
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–
1
votes
3
answers
3
Halting problem of TM which recognize recursive languages is undecidable?
Halting problem of Turing machines which recognize recursive languages is undecidable. (True / False)
Halting problem of Turing machines which recognize recursive languages is undecidable. (True / False)
gmrishikumar
1.7k
views
gmrishikumar
asked
Dec 10, 2018
Theory of Computation
decidability
recursive-and-recursively-enumerable-languages
theory-of-computation
turing-machine
rice-theorem
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–
8
votes
3
answers
4
L= {<TM> | TM halts on every input}
$L=\left \{ <TM> | TM\ halts\ on\ every\ input\ \right \}$ is above language Recursively enumerable or non recursively enumerable??
$L=\left \{ <TM | TM\ halts\ on\ every\ input\ \right \}$is above language Recursively enumerable or non recursively enumerable??
Akriti sood
4.9k
views
Akriti sood
asked
Dec 16, 2016
Theory of Computation
theory-of-computation
decidability
rice-theorem
+
–
11
votes
2
answers
5
$\{\langle M \rangle \mid M$ is a TM and there exist an input whose length is less than 100, on which $M$ halts$\}$
My Question $\{\langle M \rangle \mid M$ is a TM and there exist an input whose length is less than 100, on which $M$ halts$\}$I have to check that it is Turing Recogniza...
sourav.
4.5k
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sourav.
asked
Sep 9, 2017
Theory of Computation
theory-of-computation
turing-machine
decidability
rice-theorem
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–
0
votes
1
answer
6
Ullman (TOC) Edition 3 Exercise 9.3 Question 4 (Page No. 400)
We know by Rice's theorem that none of the following problems are decidable. However are they recursively enumerable,or non-RE? Does $L(M)$ contain at least two strings? Is $L(M)$ infinite? Is $L(M)$ a context-free language? Is $L(M) = (L(M))^{R}$?
We know by Rice's theorem that none of the following problems are decidable. However are they recursively enumerable,or non-RE?Does $L(M)$ contain at least two strings?Is...
admin
381
views
admin
asked
Jul 21, 2019
Theory of Computation
ullman
theory-of-computation
rice-theorem
descriptive
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–
1
votes
0
answers
7
Michael Sipser Edition 3 Exercise 5 Question 30 (Page No. 241)
Use Rice’s theorem, to prove the undecidability of each of the following languages. $INFINITE_{TM} = \{\langle M \rangle \mid \text{M is a TM and L(M) is an infinite language}\}$. $\{\langle M \rangle \mid \text{M is a TM and }\:1011 \in L(M)\}$. $ ALL_{TM} = \{\langle M \rangle \mid \text{ M is a TM and}\: L(M) = Σ^{\ast} \}$.
Use Rice’s theorem, to prove the undecidability of each of the following languages.$INFINITE_{TM} = \{\langle M \rangle \mid \text{M is a TM and L(M) is an infinite lan...
admin
392
views
admin
asked
Oct 20, 2019
Theory of Computation
michael-sipser
theory-of-computation
turing-machine
decidability
rice-theorem
proof
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–
0
votes
0
answers
8
Michael Sipser Edition 3 Exercise 5 Question 28 (Page No. 241)
Rice's theorem. Let $P$ be any nontrivial property of the language of a Turing machine. Prove that the problem of determining whether a given Turing machine's language has property $P$ is undecidable. In more formal terms, let $P$ be a language ... $M_{1}$ and $M_{2}$ are any $TMs$. Prove that $P$ is an undecidable language.
Rice’s theorem. Let $P$ be any nontrivial property of the language of a Turing machine. Prove that the problem of determining whether a given Turing machine’s languag...
admin
410
views
admin
asked
Oct 20, 2019
Theory of Computation
michael-sipser
theory-of-computation
turing-machine
decidability
rice-theorem
proof
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–
0
votes
0
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9
Michael Sipser Edition 3 Exercise 5 Question 29 (Page No. 241)
Rice's theorem. Let $P$ be any nontrivial property of the language of a Turing machine. Prove that the problem of determining whether a given Turing machine's language has property $P$ is undecidable. In more formal ... that $P$ is an undecidable language. Show that both conditions are necessary for proving that $P$ is undecidable.
Rice’s theorem. Let $P$ be any nontrivial property of the language of a Turing machine. Prove that the problem of determining whether a given Turing machine’s languag...
admin
456
views
admin
asked
Oct 20, 2019
Theory of Computation
michael-sipser
theory-of-computation
turing-machine
decidability
rice-theorem
proof
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–
0
votes
1
answer
10
SELF DOUBT_ RICE THEOREM
L = {<M1, M2>M1 and M2 are two TMs, and ε ∈ L(M1) \ L(M2) }. is it RECURSIVE OR RECURSIVE ENUMERABLE OR NOT EVEN RECURSIVE ENUM.
L = {<M1, M2>M1 and M2 are two TMs, and ε ∈ L(M1) \ L(M2) }.is it RECURSIVE OR RECURSIVE ENUMERABLE OR NOT EVEN RECURSIVE ENUM.
Deepanshu
943
views
Deepanshu
asked
Dec 29, 2018
Theory of Computation
rice-theorem
recursive-and-recursively-enumerable-languages
+
–
2
votes
0
answers
11
TOC-Undecidability
Here is my analysis. P1: When we bound the number of steps a turing machine can tape, the total number of input possible that can be taken by such turing machine becomes finite and by running TM in an interleaved mode I can decide whether TM M halts on x within ... decide P3. Hence, P3 is decidable.->REC. So, I think here answer must be 1. Please let me know what's right.
Here is my analysis.P1: When we bound the number of steps a turing machine can tape, the total number of input possible that can be taken by such turing machine becomes f...
Ayush Upadhyaya
979
views
Ayush Upadhyaya
asked
Nov 23, 2018
Theory of Computation
theory-of-computation
decidability
rice-theorem
+
–
0
votes
0
answers
12
Rice theorem
1.{<M>| M is a TM accepts any string starting with 1} 2.{<M>| M is TM accept exactly 20 strings} Please guide I don’t know how to apply rice theorem. for 1. Is Tyes = { string starting with 1} Tno = { all strings – strings starting with 1} what is Tyes and Tno here? I only conclude by intution that when we provide strings as input some got into loop and some got accepts .
1.{<M>| M is a TM accepts any string starting with 1}2.{<M>| M is TM accept exactly 20 strings} Please guide I don’t know how to apply rice theorem.for 1. Is Tyes = { s...
Learner_jai
606
views
Learner_jai
asked
Dec 17, 2018
Theory of Computation
rice-theorem
decidability
+
–
0
votes
0
answers
13
SELF DOUBT _ RICE THEOREM
L1 = { <M> | M is a TM and | L (M) <=1 } L2= { <M> | M is a TM and | L (M) >=1 } NOW QUESTION IS WHICH ARE RECURSIVE ENUMERABLE AND WHICH ARE NOT ???? I JUST READ BASICS OF rice theorem DONT PRACTICE MUCH QUESTIONS ON THIS I ... = 0...... and REL_yes as string length >= 1 . REL_YES is a proper subset of REL _NO . so we can say that it is also non re
L1 = { <M | M is a TM and | L (M) <=1 }L2= { <M | M is a TM and | L (M) >=1 }NOW QUESTION IS WHICH ARE RECURSIVE ENUMERABLE AND WHICH ARE NOT ????I JUST READ BASICS OF ...
Deepanshu
428
views
Deepanshu
asked
Nov 14, 2018
Theory of Computation
rice-theorem
theory-of-computation
rice
+
–
0
votes
0
answers
14
Undecidability
L1:{<M> | there exist a Turing machine M' such that <M>$\neq$<M'> and L(M) = L(M')} How this problem becomes trivial? and if it non-trivial then please explain why is that so. According to my understanding, non-trivial ... is then is it okay to say M1=M2 because they are kind of same machine but other one is just with some non deterministic nature.
L1:{<M | there exist a Turing machine M' such that <M>$\neq$<M' and L(M) = L(M')}How this problem becomes trivial? and if it non-trivial then please explain why is that s...
Swapnil Naik
560
views
Swapnil Naik
asked
Oct 30, 2018
Theory of Computation
theory-of-computation
rice-theorem
turing-machine
decidability
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–
0
votes
0
answers
15
undecidability
Writes Non Blank: Given a turing machine T, does it ever writes a non-blank symbol on its tape, when started with a blank tape. how the above problem is solvable? somewhere i got this explanation: Let the machine only writes blank symbol. Then ... is a non-trivial property of turing machine and every non trivial property of turing machine is undecidable, so this is also undecidable.
Writes Non Blank: Given a turing machine T, does it ever writes a non-blank symbol on its tape, when started with a blank tape.how the above problem is solvable?somewhere...
aambazinga
459
views
aambazinga
asked
Sep 21, 2018
Theory of Computation
theory-of-computation
decidability
rice-theorem
turing-machine
+
–
0
votes
0
answers
16
TOC- Undecidability
sidlewis
435
views
sidlewis
asked
Sep 8, 2018
Theory of Computation
theory-of-computation
decidability
rice-theorem
context-free-language
turing-machine
+
–
2
votes
2
answers
17
Undecidability Confusion
I was Studying About Undecidability on GateCSE. I am facing a doubt that : L = {<M> | M accepts "1"} L is set of String & each String is an Encoding of TM & TM accepts 1 L = {<M> | L(M) = {1}} Given a Input Program ... really is difference between both of them ? Can you definition of 2 in words like " L is set of String ............"
I was Studying About Undecidability on GateCSE. I am facing a doubt that :L = {<M | M accepts "1"} L is set of String & each String is an Encoding of TM & TM accepts 1L =...
yogi_p
883
views
yogi_p
asked
Jan 13, 2018
Theory of Computation
theory-of-computation
decidability
rice-theorem
+
–
2
votes
0
answers
18
undecidability
Define languages L0 and L1 as follows : L0={⟨M,w,0⟩∣M halts on w} L1={⟨M,w,1⟩∣M does not halt on w} Here ⟨M,w,i⟩is a triplet, whose first component M is an encoding of a Turing Machine, second component w is a string, and the third component i is a ... an acceptor for L as even when L0 is RE L1 is not RE but can anyone explain me what about L COMPLEMENT what is the language ??
Define languages L0 and L1 as follows :L0={⟨M,w,0⟩∣M halts on w}L1={⟨M,w,1⟩∣M does not halt on w}Here ⟨M,w,i⟩is a triplet, whose first component M is an e...
Venkat Sai
866
views
Venkat Sai
asked
Jan 9, 2018
Theory of Computation
theory-of-computation
decidability
rice-theorem
+
–
1
votes
0
answers
19
Rice's Theorem
What is monotonic and non-monotonic property. Please explain the second postulate of Rice's Theorem.
What is monotonic and non-monotonic property. Please explain the second postulate of Rice's Theorem.
Sumaiya23
436
views
Sumaiya23
asked
Jan 23, 2018
Theory of Computation
rice-theorem
decidability
theory-of-computation
self-doubt
turing-machine
+
–
0
votes
0
answers
20
Rice theorem problem
Problem : It is undecidable whether an arbitrary Turing Machines halt within 10 steps? Let consider Two Turing machine in which first one it is halt in 10 steps while in other it is not , so as it is undecidable. @arjun sir ,@bikram sir or @others
Problem : It is undecidable whether an arbitrary Turing Machines halt within 10 steps?Let consider Two Turing machine in which first one it is halt in 10 steps while in o...
hem chandra joshi
1.1k
views
hem chandra joshi
asked
Dec 1, 2017
Theory of Computation
rice-theorem
theory-of-computation
decidability
theorem
rice
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