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Recent questions tagged areaunderthecurve
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ISI2014DCG28
The area enclosed by the curve $\mid\: x \mid + \mid y \mid =1$ is $1$ $2$ $\sqrt{2}$ $4$
asked
Sep 23, 2019
in
Calculus
by
Arjun
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isi2014dcg
calculus
areaunderthecurve
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ISI2017MMA1
The area lying in the first quadrant and bounded by the circle $x^{2}+y^{2}=4$ and the lines $x= 0$ and $x=1$ is given by $\frac{\pi}{3}+\frac{\sqrt{3}}{2}$ $\frac{\pi}{6}+\frac{\sqrt{3}}{4}$ $\frac{\pi}{3}\frac{\sqrt{3}}{2}$ $\frac{\pi}{6}+\frac{\sqrt{3}}{2}$
asked
Apr 23, 2018
in
Calculus
by
Tesla!
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18.4k
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isi2017mma
engineeringmathematics
calculus
areaunderthecurve
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it's depends year to year
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