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Recent questions tagged floating-point-representation

8 votes
3 answers
1
A 32-bit floating-point number is represented by a 7-bit signed exponent, and a 24-bit fractional mantissa. The base of the scale factor is 16, The range of the exponent is ___________, if the scale factor is represented in excess-64 format.
asked Feb 12, 2018 in Digital Logic jothee 1.1k views
0 votes
3 answers
2
In IEEE floationg point representation, the hexadecimal number $0xC0000000$ corresponds to ? $-3.0$ $-1.0$ $-4.0$ $-2.0$
asked Feb 7, 2018 in CO and Architecture AnilGoudar 377 views
0 votes
1 answer
3
ans given= -3.75*10-1
asked Jan 29, 2018 in Digital Logic srestha 140 views
5 votes
0 answers
4
1 vote
0 answers
5
Why floating point in de-normalized normal form has range between : $\pm1\times2^{-149}$ and $\pm(1 - 2 ^{-23})\times2^{-126}$
asked Jan 13, 2018 in Digital Logic Durgesh Singh 132 views
7 votes
2 answers
6
The decimal value of 0.005 in single precision floating point format is __________________
asked Jan 6, 2018 in Digital Logic srestha 285 views
2 votes
0 answers
7
Question 1 (a) Convert the positive decimal number 17.45 to IEEE 754 single precision representation. Show all of your working out. [15 marks] (b) In IEEE 754 single precision, 1.25 is represented as: 0 01111111 01000000000000000000000 In IEEE 754 single precision 1.26 is ... IEEE 754 representation of 1.26 than 1.25. [10 marks] (c) Why is the exponent biased in IEEE representation? [5 marks]
asked Jan 5, 2018 in GATE Theo 384 views
2 votes
2 answers
8
Consider the following IEEE-754 single precision format 1 10101010 01010100................0 value represented by above number is _________________________
asked Dec 31, 2017 in Digital Logic srestha 187 views
1 vote
1 answer
10
5 votes
2 answers
11
16 bit Floating Point Representation $(-1)^{sign}*(1.M)*2^{Exp - 63}$ Sign = 1 bit Exponent = 7 bit Mantissa = 8 bit 1) Max positive number 2) Min positive number. 3) Max negative number. 4) Min negative number. 5) What is meant by precision.
asked Sep 4, 2017 in CO and Architecture Shubhanshu 1.1k views
0 votes
0 answers
12
Consider a computer system that stores a floating-point numbers with 16-bit mantissa and an 8-bit exponent, each in two’s complement. find The smallest and largest positive values which can be stored in the system.
asked Aug 31, 2017 in Digital Logic reena_kandari 211 views
0 votes
0 answers
13
Explain in detail how and what conversion(in binary bit pattern) takes place for following codes: 1) int i=37; float f=*(float *)&i; printf("f=%f",f); [Output:f=0.000000] 2)float f=7.0; short s=*(short *)&f; printf("s=%hd",s); [Output:s=0]
asked Jul 2, 2017 in Programming Veeplob Singh 235 views
0 votes
1 answer
14
IEEE 754 32 bit representation for reference:- 1. For the demoralized numbers,why the exponent is -126 and not -127? For 0 we say it is Mantissa=0 and B.E=0, so we get 0*2^0-127=0,but for any number that is having bias exponent as 0 and Mantissa non ... 127 and +128) comes under overflow and underflow condition.I mean if i am 0 or infinity or NAN then can i say that system is overflow/underflow?
asked May 22, 2017 in CO and Architecture rahul sharma 5 414 views
28 votes
4 answers
15
Given the following binary number in $32$-bit (single precision) $IEEE-754$ format : $\large 00111110011011010000000000000000$ The decimal value closest to this floating-point number is : $1.45*10^1$ $1.45*10^{-1}$ $2.27*10^{-1}$ $2.27*10^1$
asked Feb 14, 2017 in Digital Logic khushtak 8.6k views
12 votes
1 answer
16
Question 1 Explain What is Denormalized Number Give Example Give Representation in IEEE 754 and excess 64 (if any) Question 2 How to Convert $(12.625)_10$ $(12.625)_10 \Leftrightarrow (1100.101)_2$ to IEEE 754 Single Precision (With Normalization) IEEE 754 Single Precision (Without Normalization) Excess-64 (With Normalization) Excess-64 (Without Normalization)
asked Jan 25, 2017 in CO and Architecture pC 1k views
1 vote
0 answers
17
Mantissa is a pure fraction in signed magnitude form .What is the reprentation of decimal number 12.6255*102 12.6255*23 with Normalization and Without Normalization
asked Jan 24, 2017 in CO and Architecture Dulqar 477 views
1 vote
1 answer
18
Are the following statements true? 1. If Biased Exponent > Bias ,then Actual exponent is +ve. 2. If Biased Exponent < Bias ,then Actual exponent is -ve. Please tell reason also,as per me both should be false as Biased is already maximum positive number,adding something to it will cause overflow.So 1st should be -ve and second should be +ve,Please correct if I am wrong
asked Jan 21, 2017 in CO and Architecture rahul sharma 5 377 views
1 vote
1 answer
19
1 vote
0 answers
20
IN FLOATING POINT REPRESENTATION WE KNOW THAT BIAS ADDED IS THE MAXIMUM NUMBER WHICH CAN BE REPRESENTED IN 2S COMPLEMENT. Suppose exponent is represented using 8 bits, so bias added= (2^7)-1=127. But the max negative number representable with 8 bits is -128 and adding ... negative. So how do we get postitive exponent by biassing in this case??. It sounds confusing to me. Plz resolve my confusion.
asked Jan 12, 2017 in Digital Logic sushmita 376 views
4 votes
2 answers
21
7 votes
1 answer
23
Consider an excess - 50 representation for floating point numbers with $4 BCD$ digit mantissa and $2 BCD$ digit exponent in normalised form. The minimum and maximum positive numbers that can be represented are __________ and _____________ respectively.
asked Nov 27, 2016 in Digital Logic makhdoom ghaya 1.2k views
14 votes
4 answers
24
A 32-bit floating-point number is represented by a 7-bit signed exponent, and a 24-bit fractional mantissa. The base of the scale factor is 16, The range of the exponent is ___________
asked Nov 18, 2016 in Digital Logic makhdoom ghaya 3.3k views
20 votes
2 answers
25
Consider the following floating-point format. Mantissa is a pure fraction in sign-magnitude form. The normalized representation for the above format is specified as follows. The mantissa has an implicit $1$ preceding the binary (radix) point. Assume that only $0's$ are padded in while shifting a field. The ... of the above number $(0.239 \times 2^{13})$ is: $0A\;20$ $11\;34$ $49\;D0$ $4A\;E8$
asked Nov 14, 2016 in Digital Logic jothee 2.5k views
13 votes
2 answers
26
The exponent of a floating-point number is represented in excess-N code so that: The dynamic range is large. The precision is high. The smallest number is represented by all zeros. Overflow is avoided.
asked Nov 8, 2016 in Digital Logic makhdoom ghaya 1.7k views
0 votes
0 answers
27
Is question missing some data??? i am not able to figure out the exponent
asked Oct 12, 2016 in Digital Logic Rahul Jain25 183 views
3 votes
2 answers
28
The range of representable normalized numbers in the floating point binary fractional representation in a $32$-bit word with $1$-bit sign, $8$-bit excess $128$ biased exponent and $23$-bit mantissa is : $2^{-128}$ to $(1-2^{-23}) \times 2^{127}$ $(1-2^{-23}) \times 2^{-127}$ to $2^{128}$ $(1-2^{-23}) \times 2^{-127}$ to $2^{23}$ $2^{-129}$ to $(1-2^{-23}) \times 2^{127}$
asked Jul 18, 2016 in Digital Logic makhdoom ghaya 1.9k views
7 votes
1 answer
29
What is the decimal value of the floating-point number $C1D00000$ (hexadecimal notation)? (Assume $32$-bit, single precision floating point $\text{IEEE}$ representation) $28$ $-15$ $-26$ $-28$
asked Jun 21, 2016 in Digital Logic jothee 4.1k views
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