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8 votes
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1
Ten chocolates are distributed randomly among three children standing in a row. The probability that the first child receives exactly three chocolates is $\frac{5 \times 2^{11}}{3^9}$ $\frac{5 \times 2^{10}}{3^9}$ $\frac{1}{3^9}$ $\frac{1}{3}$
asked Oct 22, 2017 in Probability cocgame1 855 views
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