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Recent questions tagged ip-packet

0 votes
1 answer
1
A $64000$-byte message is to be transmitted over a $2$-hop path in a store-and-forward packet-switching network. The network limits packets toa maximum size of $2032$ bytes including a $32$-byte header. The trans-mission lines in the network are error free and have a speed of $50$ Mbps. ... getting answer as $1*3*(T_t+T_p) + \;31*T_t$ where $T_t=0.325\; ms$ and $T_p=3.333\; ms$. Please Confirm.
asked Mar 25, 2019 in Computer Networks ankitgupta.1729 241 views
1 vote
0 answers
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Say Client buffer is of 12000 Bytes and MSS is 1200 B and this info is sent to server and now server send the info in (SYN +ACK) segment as Server Buffer = 18000 B and MSS is 600 B Now in data transfer phase does both Client and Server will choose 600 Bytes data segments ... ) = Min (1200, 600) = 600 Bytes? Or does the sever will send 1200 Bytes segments to C and C sends 600 B segments to server?
asked Dec 16, 2018 in Computer Networks iarnav 156 views
0 votes
2 answers
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1 vote
3 answers
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I was studying how the packet is transmitted from source to destination, what i understood is, we need IP address to identify the network in which our destination is present, while MAC address (data link layer address) is used for hop to hop communication. On reaching ... (https://www.thewindowsclub.com/change-mac-address-in-windows). How is it possible if MAC address is present in the NIC?
asked Oct 19, 2018 in Computer Networks Ollie 447 views
2 votes
1 answer
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It is known that any network can only transmit data packet size equal to (or less than) MTU allowed in the network. If that is the case, and if we have a Path MTU discovery in place, why is there is need for MSS in TCP layer. Why does it ... ? Setting MSS different (read larger) than MTU, will only burden Network Layer with fragmentation overhead. Is there any significant advantage of using MSS ?
asked Feb 6, 2018 in Computer Networks Arunav Khare 473 views
1 vote
0 answers
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4 votes
1 answer
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If a datagram of size 4000 bytes from transport layer arrives at network layer and it has to be forwarded through a link with maximum capacity of 800 bytes. Then calculate the number of fragments needed if the header size is 20 bytes. Also calculate the data size of the last fragment.
asked Jan 2, 2018 in Computer Networks MIRIYALA JEEVAN KUMA 366 views
1 vote
1 answer
9
Consider station “A” send data to station “B”. Data frame contain MAC address, IP address and port address. Which of the following address may change on intermediate router A Destination IP address B Destination MAC C Source MAC D Source IP address
asked Dec 30, 2017 in Computer Networks rahul sharma 5 273 views
0 votes
1 answer
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IP packets whose total length (data plus header) is 16Kb basting out of a router live for 15 seconds. The maximum line speed (in MBPS) of the router can operate at without cycling through the IP datagram identification number space is? Please help and I am stuck due to 16Kb . What I know Identification number is 16 bit in IP. Wrap around Time=Number of byte/Bandwidth. Thanks :)
asked Dec 12, 2017 in Computer Networks sunil sarode 861 views
0 votes
2 answers
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Suppose a packet of length 1800 bytes with minimum header size enter a local area network with MTU (Maximum transfer unit ) of 500 bytes, then how many fragments will be generated from the packet and what is size of the payload of the last packet ?
asked Dec 11, 2017 in Computer Networks Warlock lord 339 views
1 vote
1 answer
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1 answer
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When the IP packet has minimum size (20bytes), what happens to option field. Is it not present or present with all bits set to 0 (all 40bytes of 0's)?
asked Sep 6, 2017 in Computer Networks Mayank Joshi 372 views
0 votes
2 answers
14
I am reading Forouzan in that I have stuck here, I know that. TCP is connection oriented service, means it all segments follow same path, and segments are in order delivered. But it says that TCP segments is encapsulated in IP packets and since IP is ... its packet follow different path. How it is happening. Consider this screen shot of Forouzan:- Please explain the proper reason behind it.
asked Aug 23, 2017 in Computer Networks Shubhanshu 597 views
0 votes
1 answer
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Are these definations of MSS and MTU correct?? MSS is maximum payload of TCP segment. TCP segment (MSS + TCP header) For IPpacket, it consists of (MSS + TCP header + IP header) And payload of IP packet means (TCPheader + MSS) Ethernet frame packet is (Frame header ... MSS) Also is fragmentation always done at router?? Can it be done by source?? I am really confused about these terms. Plz verify.
asked Feb 8, 2017 in Computer Networks Rahul Jain25 1.7k views
7 votes
5 answers
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Suppose datagrams are limited to 1,500 bytes (including header) between source Host A and destination Host B. Assuming a 20-byte IP header and a 20-byte TCP header, how many datagrams would be required to send an MP3 consisting of 4 million bytes?
asked Feb 7, 2017 in Computer Networks smartmeet 1.7k views
3 votes
3 answers
17
4 votes
1 answer
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Which of the following is used in the options field of $IPv4$? Strict source routing Loose source routing Time stamp All of the above
asked Jul 12, 2016 in Computer Networks makhdoom ghaya 1.4k views
0 votes
3 answers
20
If a packet arrive with M-bit value is ‘1’ and a fragmentation offset value ‘0’, then it is ____ fragement. First Middle Last All of the above
asked Jul 8, 2016 in Computer Networks jothee 2.2k views
9 votes
5 answers
21
An IP packet has arrived with the first 8 bits as 0100 0010. Which of the following is correct? The number of hops this packet can travel is 2. The total number of bytes in header is 16 bytes The upper layer protocol is ICMP The receiver rejects the packet
asked Jun 28, 2016 in Computer Networks shivanisrivarshini 3.6k views
3 votes
4 answers
22
Use of IPSEC in tunnel mode results in IP packet with same header IP packet with new header IP packet without header No changes in IP packet
asked May 30, 2016 in Computer Networks Anuanu 1.9k views
23 votes
6 answers
23
An IP datagram of size $1000$ $\text{bytes }$arrives at a router. The router has to forward this packet on a link whose MTU (maximum transmission unit) is $100$ $\text{bytes }$. Assume that the size of the IP header is $20$ $\text{bytes }.$ The number of fragments that the IP datagram will be divided into for transmission is________.
asked Feb 12, 2016 in Computer Networks Sandeep Singh 6.2k views
3 votes
1 answer
24
A Router outside the organization received a packet 224.240.7.91. Consider following steps that a router may take: 1. The router looks in its routing table to find out how to route the packet to the destination 2. The router looks at the first byte of the address to ... not be taken. So the router should take only step 1. Am I missing something? What should be the correct answer to this question?
asked Dec 5, 2015 in Computer Networks अनुराग पाण्डेय 460 views
6 votes
4 answers
25
A IP packet has arrived in which the fragmentation offset value is 100,the value of HLEN is 5 and the value of total length field is 200. What is the number of the last byte? 194 394 979 1179
asked Sep 23, 2015 in Computer Networks ajit 5.1k views
56 votes
9 answers
26
$\text{Host A}$ sends a $\text{UDP}$ datagram containing $8880\text{ bytes}$ of user data to $\text{host B}$ over an $\text{Ethernet LAN}.$ Ethernet frames may carry data up to $1500\text{ bytes (i.e. MTU = 1500 bytes)}.$ Size of $\text{UDP}$ ... and what will be the contents of offset field in the last fragment? $6$ and $925$ $6$ and $7400$ $7$ and $1110$ $7$ and $8880$
asked Feb 13, 2015 in Computer Networks jothee 9.9k views
25 votes
6 answers
27
Which of the following fields of an IP header is NOT modified by a typical IP router? Check sum Source address Time to Live (TTL) Length
asked Feb 13, 2015 in Computer Networks makhdoom ghaya 3.8k views
19 votes
5 answers
28
In the TCP/IP protocol suite, which one of the following is NOT part of the IP header? Fragment Offset Source IP address Destination IP address Destination port number
asked Nov 2, 2014 in Computer Networks Ishrat Jahan 2.2k views
14 votes
5 answers
29
One of the header fields in an IP datagram is the Time-to-Live (TTL) field. Which of the following statements best explains the need for this field? It can be used to prioritize packets. It can be used to reduce delays. It can be used to optimize throughput. It can be used to prevent packet looping.
asked Sep 29, 2014 in Computer Networks jothee 2.6k views
36 votes
9 answers
30
An $IP$ router with a $\text{Maximum Transmission Unit (MTU)}$ of $1500$ bytes has received an $IP$ packet of size $4404\text{ bytes}$ with an $IP$ header of length $20\text{ bytes}$. The values of the relevant fields in the header of the third $IP$ fragment generated by the ... $1,$ Datagram Length$: 1500;$ Offset$: 370$ $\text{MF bit}$: $0,$ Datagram Length$: 1424;$ Offset$: 2960$
asked Sep 28, 2014 in Computer Networks jothee 8.2k views
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