Login
Register
Dark Mode
Brightness
Profile
Edit Profile
Messages
My favorites
My Updates
Logout
Recent questions tagged kenneth-rosen
0
votes
1
answer
721
Kenneth Rosen Edition 7 Exercise 1.7 Question 15 (Page No. 91)
Use a proof by contraposition to show that if $x+y≥2$,where $x$ and $y$ are real numbers, then $x≥1$ or $y≥1$.
Use a proof by contraposition to show that if $x+y≥2$,where $x$ and $y$ are real numbers, then $x≥1$ or $y≥1$.
Pooja Khatri
470
views
Pooja Khatri
asked
Apr 4, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
0
votes
0
answers
722
Kenneth Rosen Edition 7 Exercise 1.7 Question 14 (Page No. 91)
Prove that if $x$ is rational and $x\neq0$ , then $1/x$ is rational.
Prove that if $x$ is rational and $x\neq0$ , then $1/x$ is rational.
Pooja Khatri
175
views
Pooja Khatri
asked
Apr 4, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
0
votes
0
answers
723
Kenneth Rosen Edition 7 Exercise 1.7 Question 13 (Page No. 91)
Prove that if $x$ is irrational, then $1/x$ is irrational.
Prove that if $x$ is irrational, then $1/x$ is irrational.
Pooja Khatri
206
views
Pooja Khatri
asked
Apr 4, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
0
votes
0
answers
724
Kenneth Rosen Edition 7 Exercise 1.7 Question 12 (Page No. 91)
Prove or disprove that the product of a nonzero rational number and an irrational number is irrational.
Prove or disprove that the product of a nonzero rational number and an irrational number is irrational.
Pooja Khatri
329
views
Pooja Khatri
asked
Apr 4, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
1
votes
1
answer
725
Kenneth Rosen Edition 7 Exercise 1.7 Question 11 (Page No. 91)
Prove or disprove that the product of two irrational numbers is irrational.
Prove or disprove that the product of two irrational numbers is irrational.
Pooja Khatri
300
views
Pooja Khatri
asked
Apr 4, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
1
votes
1
answer
726
Kenneth Rosen Edition 7 Exercise 1.7 Question 10 (Page No. 91)
Use a direct proof to show that the product of two rational numbers is rational.
Use a direct proof to show that the product of two rational numbers is rational.
Pooja Khatri
2.6k
views
Pooja Khatri
asked
Apr 4, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
0
votes
0
answers
727
Kenneth Rosen Edition 7 Exercise 1.7 Question 9 (Page No. 91)
Use a proof by contradiction to prove that the sum of an irrational number and a rational number is irrational.
Use a proof by contradiction to prove that the sum of an irrational number and a rational number is irrational.
Pooja Khatri
186
views
Pooja Khatri
asked
Apr 4, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
0
votes
0
answers
728
Kenneth Rosen Edition 7 Exercise 1.7 Question 8 (Page No. 91)
Prove that if $n$ is a perfect square, then $n+2$ is not a perfect square
Prove that if $n$ is a perfect square, then $n+2$ is not a perfect square
Pooja Khatri
155
views
Pooja Khatri
asked
Apr 4, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
0
votes
1
answer
729
Discrete Mathematics by Kenneth Rossen 7th Ed. Chapter 1 Page 89 Example 8
kaveeshnyk
660
views
kaveeshnyk
asked
Apr 1, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
0
votes
0
answers
730
#KennethRosen#DiscreteMaths
R is iff $R ^{-1}$ is Total ? a function ? a surjection ? an injection ? a bijection ? Fill in the entries in the table.
R isiff $R ^{-1}$ isTotal?a function?a surjection?an injection?a bijection?Fill in the entries in the table.
Sumiran Agrawal
256
views
Sumiran Agrawal
asked
Mar 30, 2019
Set Theory & Algebra
relations
kenneth-rosen
+
–
1
votes
3
answers
731
Proposition Logic-Rosen(7e)
Show that these statements are inconsistent: “If Miranda does not take a course in discrete mathematics, then she will not graduate.” “If Miranda does not graduate, then she is not qualified for the job.” “If Miranda reads this book, then she is qualified for the job.” “Miranda does not take a course in discrete mathematics but she reads this book.” how to approach?
Show that these statements are inconsistent: “If Miranda does not take a course in discrete mathematics, then she will not graduate.” “If Miranda does not graduate,...
aditi19
2.6k
views
aditi19
asked
Mar 26, 2019
Mathematical Logic
mathematical-logic
discrete-mathematics
kenneth-rosen
propositional-logic
+
–
0
votes
1
answer
732
Kenneth Rosen Edition 7 Exercise 1.7 Question 7 (Page No. 91)
Use a direct proof to show that every odd integer is the difference of two squares.
Use a direct proof to show that every odd integer is the difference of two squares.
Pooja Khatri
897
views
Pooja Khatri
asked
Mar 20, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
0
votes
0
answers
733
Kenneth Rosen Edition 7 Exercise 1.7 Question 6 (Page No. 91)
Use a direct proof to show that the product of two odd numbers is odd.
Use a direct proof to show that the product of two odd numbers is odd.
Pooja Khatri
211
views
Pooja Khatri
asked
Mar 20, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
1
votes
1
answer
734
Kenneth Rosen Edition 7 Exercise 1.7 Question 5 (Page No. 91)
Prove that if $m+n$ and $n+p$ are even integers, where $m, n$,and $p$ are integers, then $m+p$ is even. What kind of proof did you use?
Prove that if $m+n$ and $n+p$ are even integers, where $m, n$,and $p$ are integers, then $m+p$ is even. What kind of proof did you use?
Pooja Khatri
235
views
Pooja Khatri
asked
Mar 20, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
0
votes
0
answers
735
Kenneth Rosen Edition 7 Exercise 1.7 Question 4 (Page No. 91)
Show that the additive inverse, or negative, of an even number is an even number using a direct proof.
Show that the additive inverse, or negative, of an even number is an even number using a direct proof.
Pooja Khatri
289
views
Pooja Khatri
asked
Mar 20, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
0
votes
1
answer
736
Kenneth Rosen Edition 7 Exercise 1.7 Question 3 (Page No. 91)
Show that the square of an even number is an even number using a direct proof
Show that the square of an even number is an even number using a direct proof
Pooja Khatri
270
views
Pooja Khatri
asked
Mar 20, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
+
–
0
votes
0
answers
737
Kenneth Rosen Edition 7 Exercise 1.7 Question 2 (Page No. 91)
Use a direct proof to show that the sum of two even integers is even.
Use a direct proof to show that the sum of two even integers is even.
Pooja Khatri
193
views
Pooja Khatri
asked
Mar 20, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
+
–
1
votes
1
answer
738
Kenneth Rosen Edition 7 Exercise 1.7 Question 1 (Page No. 91)
Use a direct proof to show that the sum of two odd integers is even.
Use a direct proof to show that the sum of two odd integers is even.
Pooja Khatri
368
views
Pooja Khatri
asked
Mar 20, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
+
–
0
votes
1
answer
739
Kenneth Rosen Edition 7 Exercise 1.6 Question 35 (Page No. 80)
Determine whether this argument, taken from Kalish and Montague [KaMo64], is valid. If Superman were able and willing to prevent evil,he would do so. If Superman were unable to prevent evil, he would be impotent; if ... does not prevent evil. If Superman exists, he is neither impotent nor malevolent. Therefore, Superman does not exist.
Determine whether this argument, taken from Kalish and Montague [KaMo64], is valid.If Superman were able and willing to prevent evil,he would do so. If Superman were unab...
Pooja Khatri
1.2k
views
Pooja Khatri
asked
Mar 20, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
propositional-logic
mathematical-logic
difficult
+
–
0
votes
1
answer
740
Kenneth Rosen Edition 7 Exercise 1.6 Question 34 (Page No. 80)
The Logic Problem, taken from WFF'N PROOF, The Game of Logic, has these two assumptions:1. Logic is difficult or not many students like logic. 2. If mathematics is easy, then logic is not difficult. By translating these ... not easy. That if not many students like logic, then either mathematics is not easy or logic is not difficult.
The Logic Problem, taken from WFF’N PROOF, The Game of Logic, has these two assumptions:1. “Logic is difficult or not many students like logic.”2. “If mathematics...
Pooja Khatri
882
views
Pooja Khatri
asked
Mar 20, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
difficult
+
–
0
votes
1
answer
741
Kenneth Rosen Edition 7 Exercise 1.6 Question 33 (Page No. 80)
Use resolution to show that the compound proposition $(p \vee q) \wedge (\sim p \vee q) \wedge (p \vee \sim q) \wedge (\sim p \vee \sim q)$ is not satisfiable.
Use resolution to show that the compound proposition $(p \vee q) \wedge (\sim p \vee q) \wedge (p \vee \sim q) \wedge (\sim p \vee \sim q)$ is not satisfiable.
Pooja Khatri
745
views
Pooja Khatri
asked
Mar 20, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
0
votes
0
answers
742
Kenneth Rosen Edition 7 Exercise 1.6 Question 32 (Page No. 80)
Show that the equivalence $p \wedge \sim p \equiv F$ can be derived using resolution together with the fact that a conditional statement with a false hypothesis is true. [Hint:Let $q=r=F$ in resolution.]
Show that the equivalence $p \wedge \sim p \equiv F$ can be derived using resolution together with the fact that a conditional statement with a false hypothesis is true. ...
Pooja Khatri
346
views
Pooja Khatri
asked
Mar 20, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
1
votes
1
answer
743
Kenneth Rosen Edition 7 Exercise 1.6 Question 31 (Page No. 80)
Use resolution to show that the hypotheses “It is not raining or Yvette has her umbrella,” “Yvette does not have her umbrella or she does not get wet,” and “It is raining or Yvette does not get wet” imply that “Yvette does not get wet.”
Use resolution to show that the hypotheses “It is not raining or Yvette has her umbrella,” “Yvette does not have her umbrella or she does not get wet,” and “It ...
Pooja Khatri
1.5k
views
Pooja Khatri
asked
Mar 20, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
0
votes
1
answer
744
Kenneth Rosen Edition 7 Exercise 1.6 Question 30 (Page No. 80)
Use resolution to show the hypotheses “Allen is a bad boy or Hillary is a good girl” and “Allen is a good boy or David is happy” imply the conclusion “Hillary is a good girl or David is happy.”
Use resolution to show the hypotheses “Allen is a bad boy or Hillary is a good girl” and “Allen is a good boy or David is happy” imply the conclusion “Hillary i...
Pooja Khatri
1.8k
views
Pooja Khatri
asked
Mar 20, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
0
votes
0
answers
745
Kenneth Rosen Edition 7 Exercise 1.6 Question 29 (Page No. 80)
Use rules of inference to show that if $\forall x (P(x) \vee Q(x))$, $\forall x (\sim Q(x) \vee S(x)), \forall x (R(x) \rightarrow \sim S(x)),$ and $\exists x \sim P(x)$ are true, then $\exists x \sim R(x)$ is true.
Use rules of inference to show that if $\forall x (P(x) \vee Q(x))$, $\forall x (\sim Q(x) \vee S(x)), \forall x (R(x) \rightarrow \sim S(x)),$ and $\exists x \sim P(x)$ ...
Pooja Khatri
281
views
Pooja Khatri
asked
Mar 20, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
3
votes
1
answer
746
Kenneth Rosen Edition 7 Exercise 1.6 Question 28 (Page No. 80)
Use rules of inference to show that if $\forall x (P(x) \vee Q(x))$ and $\forall x ((\sim P(x) \wedge Q(x)) \rightarrow R(x))$ are true, then $\forall x (\sim R(x) \rightarrow P(x))$ is also true, where the domains of all quantifiers are the same.
Use rules of inference to show that if $\forall x (P(x) \vee Q(x))$ and $\forall x ((\sim P(x) \wedge Q(x)) \rightarrow R(x))$ are true, then $\forall x (\sim R(x) \right...
Pooja Khatri
444
views
Pooja Khatri
asked
Mar 19, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
0
votes
0
answers
747
Kenneth Rosen Edition 7 Exercise 1.6 Question 27 (Page No. 80)
Use rules of inference to show that if $\forall x (P(x) \rightarrow (Q(x) \wedge S(x)))$ and $\forall x ( P(x) \wedge R(x))$ are true, then $\forall x (R(x) \wedge S(x))$ is true.
Use rules of inference to show that if $\forall x (P(x) \rightarrow (Q(x) \wedge S(x)))$ and $\forall x ( P(x) \wedge R(x))$ are true, then $\forall x (R(x) \wedge S(x))$...
Pooja Khatri
219
views
Pooja Khatri
asked
Mar 19, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
0
votes
0
answers
748
Kenneth Rosen Edition 7 Exercise 1.6 Question 26 (Page No. 80)
Justify the rule of universal transitivity, which states that if $\forall x (P(x) \rightarrow Q(x))$ and $\forall x(Q(x) \rightarrow R(x))$ are true, then $\forall x (P(x) \rightarrow R(x))$ is true, where the domains of all quantifiers are the same.
Justify the rule of universal transitivity, which states that if $\forall x (P(x) \rightarrow Q(x))$ and $\forall x(Q(x) \rightarrow R(x))$ are true, then $\forall x (P(x...
Pooja Khatri
220
views
Pooja Khatri
asked
Mar 19, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
0
votes
0
answers
749
Kenneth Rosen Edition 7 Exercise 1.6 Question 25 (Page No. 80)
Justify the rule of universal modus tollens by showing that the premises $ \forall x (P(x) \rightarrow Q(x)) $ and $\sim Q(a)$for $a$ particular element $a$ in the domain, imply $\sim P(a)$
Justify the rule of universal modus tollens by showing that the premises $ \forall x (P(x) \rightarrow Q(x)) $ and $\sim Q(a)$for $a$ particular element $a$ in the domain...
Pooja Khatri
294
views
Pooja Khatri
asked
Mar 19, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
0
votes
0
answers
750
Kenneth Rosen Edition 7 Exercise 1.6 Question 18 (Page No. 79)
What is wrong with this argument? Let $S(x, y)$ be “$x$ is shorter than $y$.” Given the premise $\exists s S(s, Max)$, it follows that $S(Max, Max)$. Then by existential generalization it follows that $\exists x S(x,x)$, so that someone is shorter than himself.
What is wrong with this argument? Let $S(x, y)$ be “$x$ is shorter than $y$.” Given the premise $\exists s S(s, Max)$, it follows that $S(Max, Max)$. Then by existent...
Pooja Khatri
465
views
Pooja Khatri
asked
Mar 19, 2019
Mathematical Logic
kenneth-rosen
discrete-mathematics
mathematical-logic
propositional-logic
+
–
Page:
« prev
1
...
20
21
22
23
24
25
26
27
28
29
30
...
39
next »
Email or Username
Show
Hide
Password
I forgot my password
Remember
Log in
Register