Consider the following program fragment for reversing the digits in a given integer to obtain a new integer. Let $n = d_1\, d_2\, \ldots\, d_m$. int n, rev; rev = 0; while(n > 0) { rev = rev * 10 + n%10; n = n/10; } The loop invariant condition at the end of the $i^{th}$ ... $n \neq \text{rev}$ $n=d_1\, d_2 \,\ldots\, d_m \qquad \mathbf{or} \qquad \text{rev} =d_m \,\ldots\, d_2\, d_1$

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Sep 19, 2014
in Programming
Kathleen
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