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Recent questions tagged made-easy-test-series
2
votes
9
answers
1561
MadeEasy Test Series: Computer Networks - Flow Control Methods
Station X needs to send a message consisting of 12 packets to station Y using a sliding window protocol (Window Size 4) and Go back n error control strategy. All packets are ready and immediately available for transmission. If every ... gets lost), then the number of packets that X will transmit for sending the message to Y are _____.
Station X needs to send a message consisting of 12 packets to station Y using a sliding window protocol (Window Size 4) and Go back n error control strategy. All packets ...
nvnverma18
2.2k
views
nvnverma18
asked
Sep 23, 2016
Computer Networks
made-easy-test-series
computer-networks
flow-control-methods
sliding-window
+
–
0
votes
0
answers
1562
TestSeries :
Hello everyone, What is the frequency of repition of questions in MadeEasy and ACE test series? Iam getting very low marks around 10/25(chapter test) in madeEasy that makes me think that maybe questions are repeated and topper in test completed 45min. test in 18minutes. Please guide me. Thanks in advance.
Hello everyone, What is the frequency of repition of questions in MadeEasy and ACE test series? Iam getting very low marks around 10/25(chapter test) in madeEasy that mak...
robertSingh
1.1k
views
robertSingh
asked
Sep 22, 2016
Others
test-series
ace-test-series
made-easy-test-series
+
–
1
votes
1
answer
1563
MadeEasy Test Series: Operating System - File System
In particular Unix OS, each data block is 256 bits, each node has 4 direct data block addresses and 3 additional addresses: One for single indirect block, one for double indirect block and one for triple indirect block. Each block is addressed with 64-bit. The total size of a file possible in the file system (in k-bits) is________.
In particular Unix OS, each data block is 256 bits, each node has 4 direct data block addresses and 3 additional addresses: One for single indirect block, one for double ...
mcjoshi
581
views
mcjoshi
asked
Sep 17, 2016
Operating System
made-easy-test-series
operating-system
file-system
+
–
7
votes
1
answer
1564
MadeEasy Test Series 2017: Operating System - Process Schedule
As Operating system uses round robin process scheduling algorithm. Consider the execution times for the following processes. ... execution in one cycle only". If this statement is neglected then definitely answer is $5$ ( simple RR algorithm)
As Operating system uses round robin process scheduling algorithm. Consider the execution times for the following processes.$\begin{array}{|c|cl|}\hline \text{Process Id...
mcjoshi
638
views
mcjoshi
asked
Sep 17, 2016
Operating System
made-easy-test-series
operating-system
process-scheduling
+
–
2
votes
1
answer
1565
MadeEasy Test Series: Combinatory - Permutations And Combinations
Number of 10 bit binary string where the string contains 3 consecutive 0's or 3 consecutive 1's?
Number of 10 bit binary string where the string contains 3 consecutive 0's or 3 consecutive 1's?
Shreya Roy
486
views
Shreya Roy
asked
Sep 16, 2016
Combinatory
made-easy-test-series
engineering-mathematics
discrete-mathematics
combinatory
+
–
2
votes
3
answers
1566
MadeEasy Test Series 2017: Computer Networks - Flow Control Methods
Consider a network connecting two systems located 4000 kilometers apart. The bandwidth of the network is 64 Mbps. The propagation speed of the media is 2/3 of the speed of light in vacuum. It is needed to design selective ... at nodes are negligible. Then, the minimum size in bits of the sequence number field has to be _________.
Consider a network connecting two systems located 4000 kilometers apart. The bandwidth of the network is 64 Mbps. The propagation speed of the media is 2/3 of the speed o...
Pankaj Joshi
2.1k
views
Pankaj Joshi
asked
Sep 7, 2016
Computer Networks
made-easy-test-series
computer-networks
flow-control-methods
sliding-window
selective-repeat
+
–
6
votes
3
answers
1567
MadeEasy Test Series 2017: Computer Networks - Congestion Control
Consider the effect of using slow start on a line with 10 msec round trip time. The receiver window and the size of congestion window are set to 38 KB and 36 KB respectively. Sender side threshold is set to 18 KB. After 8 ... to send first full window of 18 KB is______ Assume window size at the start of slow start phase is 2 KB.
Consider the effect of using slow start on a line with 10 msec round trip time. The receiver window and the size of congestion window are set to 38 KB and 36 KB respectiv...
Pankaj Joshi
2.3k
views
Pankaj Joshi
asked
Sep 7, 2016
Computer Networks
made-easy-test-series
computer-networks
congestion-control
+
–
5
votes
1
answer
1568
MadeEasy Test Series 2017: Computer Networks - Application Layer Protocols
Suppose you needed to use HTTP to download a webpage with three embedded images. The total number messages saved between the client and server starting from initiates TCP connection to receive the third object and close connection when using persistent HTTP without pipelining insteed of non-persistent HTTP are
Suppose you needed to use HTTP to download a webpage with three embedded images. The total number messages saved between the client and server starting from initiates TCP...
Pankaj Joshi
4.9k
views
Pankaj Joshi
asked
Sep 7, 2016
Computer Networks
made-easy-test-series
computer-networks
application-layer-protocols
http
+
–
13
votes
2
answers
1569
MadeEasy Test Series 2017: Computer Networks - Ethernet
Assume that X and Y are the only two stations on an Ethernet. Each has a steady queue of frames to send. Both X and Y attempt to transmit a frame, they wait to get the control of channel using binary exponential algorithm. The ... fifth round of the algorithm (assuming every time both X and Y will collide in back-off race till 4th round) is
Assume that X and Y are the only two stations on an Ethernet. Each has a steady queue of frames to send. Both X and Y attempt to transmit a frame, they wait to get the co...
Pankaj Joshi
3.8k
views
Pankaj Joshi
asked
Sep 7, 2016
Computer Networks
made-easy-test-series
computer-networks
ethernet
+
–
1
votes
1
answer
1570
MadeEasy Test Series: Operating System - File System
A file system with 512 GB disk uses a file descriptor with 16 direct block addresses, 1 indirect block address, 1 doubly indirect block address, 1 triple indirect block address. Size of each disk block is 256 bytes. And size of each disk block ... in GB) My answer is 0.008 GB In their solution, they say it's 8 GB, which I think is wrong.
A file system with 512 GB disk uses a file descriptor with 16 direct block addresses, 1 indirect block address, 1 doubly indirect block address, 1 triple indirect block a...
tvkkk
544
views
tvkkk
asked
Aug 29, 2016
Operating System
made-easy-test-series
operating-system
file-system
+
–
5
votes
1
answer
1571
MadeEasy Workbook: CO & Architecture - Machine Instructions
In the program below, the number of times the FIRST and SECOND JNZ instructions cause the control to be transferred to LOOP respectively MVI H, 02H MVI L, 05H LOOP: DCR L ; Decrement L by 1 FIRST: JNZ LOOP DCR H SECOND: JNZ LOOP 5 and 2 4 and 1 259 and 1 260 and 1
In the program below, the number of times the FIRST and SECOND JNZ instructions cause the control to be transferred to LOOP respectively MVIH, 02H MVIL, 05HLOOP:DCR...
Shubham Sharma 2
1.4k
views
Shubham Sharma 2
asked
Aug 27, 2016
CO and Architecture
made-easy-test-series
co-and-architecture
machine-instruction
+
–
1
votes
1
answer
1572
MadeEasy Test Series: Computer Networks - Network Communication
what is latency in data transmission(in microsec)with the following parameters. fibre optics link of 20 km, packet size to 2KB, bandwidth = 100 mbps one switch in the link with constant delay of 40 microsec velocity = 2*10^8 m/s. (a) 200 (b) 250 (c) 275 (d) 300
what is latency in data transmission(in microsec)with the following parameters. fibre optics link of 20 km, packet size to 2KB, bandwidth = 100 mbps one switch in the lin...
cse7
572
views
cse7
asked
Aug 25, 2016
Computer Networks
made-easy-test-series
computer-networks
network-communication
+
–
3
votes
1
answer
1573
MadeEasy Test Series: Computer Networks - Flow Control Methods
consider a link of length 1000 km with 10^9 bps rate connecting a sender and receiver. assume a fixed packet length of 1250 bytes and sender always has packet to send. packet are never lost or corrupted in the connection. what is the ... window protocol? assume signal propagation is 5 microsec per km (A) 100 (B) 1000 (C) 110 (D) 1100
consider a link of length 1000 km with 10^9 bps rate connecting a sender and receiver. assume a fixed packet length of 1250 bytes and sender always has packet to send. pa...
cse7
1.5k
views
cse7
asked
Aug 25, 2016
Computer Networks
made-easy-test-series
computer-networks
flow-control-methods
sliding-window
+
–
1
votes
1
answer
1574
#made easy
Big oh estimate for f(x)=(x+1)log($x^2 +1$)+3$x^2$ is given as 1.O(xlogx) 2.O($x^2$) 3.O($x^3$) 4O($x^2$logx)
Big oh estimate forf(x)=(x+1)log($x^2 +1$)+3$x^2$ is given as1.O(xlogx)2.O($x^2$)3.O($x^3$)4O($x^2$logx)
Hira Thakur
981
views
Hira Thakur
asked
Aug 14, 2016
Algorithms
algorithms
asymptotic-notation
logarithmic-function
made-easy-test-series
+
–
1
votes
1
answer
1575
#made easy
soluation for the recurrence relation is f(x)=2T(floor(rootn))+logn 1.O(nlogloglogn) 2.O(nloglogn) 3.O(loglogn) 4O(lognloglogn)
soluation for the recurrence relation isf(x)=2T(floor(rootn))+logn1.O(nlogloglogn)2.O(nloglogn)3.O(loglogn)4O(lognloglogn)
Hira Thakur
334
views
Hira Thakur
asked
Aug 14, 2016
Algorithms
made-easy-test-series
recurrence-relation
+
–
2
votes
1
answer
1576
made easy
which is true about huffman coding- 1.Huffman coding may become loss in some time 2.in Huffman coding no code is prefix of any other code 3.huffman code may not be optimal lossless code in some case 4.all of above
which is true about huffman coding-1.Huffman coding may become loss in some time2.in Huffman coding no code is prefix of any other code3.huffman code may not be optimal l...
Hira Thakur
575
views
Hira Thakur
asked
Aug 14, 2016
Algorithms
huffman-code
made-easy-test-series
+
–
6
votes
1
answer
1577
MadeEasy Test Series: Theory Of Computation - Grammar
I am not getting how one of it is CLG & rest 2 are regular plz someone explain this..... thnks in advance...
I am not getting how one of it is CLG & rest 2 are regularplz someone explain this.....thnks in advance...
dileswar sahu
633
views
dileswar sahu
asked
Aug 9, 2016
Theory of Computation
made-easy-test-series
test-series
theory-of-computation
grammar
+
–
1
votes
0
answers
1578
MadeEasy Workbook: Computer Networks - Flow Control Methods
If the size of window is N and N # of frames are transmitted and it is supporting cumulative ACK. The Ack no. that is transmitted is ACK p.Then Calculate a)how many frames are received to the receiver b) How many frames are ... it using GOBACKN and my answer is not matching to his answer plus approach is diff. Anybody ??? help me on this.
If the size of window is N and N # of frames are transmitted and it is supporting cumulative ACK. The Ack no. that is transmitted is ACK p.ThenCalculatea)how many frames ...
mohit chawla
664
views
mohit chawla
asked
Jul 25, 2016
Computer Networks
made-easy-test-series
computer-networks
flow-control-methods
+
–
2
votes
1
answer
1579
made easy test 2015 qno-21
Consider the following statements: Let T be a minimum spanning tree of a graph G. Then for any two vertices u and v the path from u to v in T is the shortest path from u to v in the graph G Suppose that average edge weight for a graph G is ... above statements are true? Only I Only II both I and II None of these plz give one one counter example of both option I & II
Consider the following statements:Let T be a minimum spanning tree of a graph G. Then for any two vertices u and v the path from u to v in T is the shortest path from u t...
dileswar sahu
576
views
dileswar sahu
asked
Jul 19, 2016
Algorithms
algorithms
minimum-spanning-tree
made-easy-test-series
+
–
1
votes
0
answers
1580
MadeEasy Test Series 2015: Algorithms - Graph Algorithms
Here i have option III is doubt.how option III always correct.one counter example is if i choose a tree where s is root node and v1& v2 are its child node then above question property i.e the vertices V1 and V2 that are simultaneously ... from vertex s in a digraph is satisfies.but there is no any path from v1 to v2 or from v2 to v1.
Here i have option III is doubt.how option III always correct.one counter example is if i choose a tree where s is root node and v1& v2 are its child node then above ques...
dileswar sahu
821
views
dileswar sahu
asked
Jul 19, 2016
Algorithms
made-easy-test-series
algorithms
graph-algorithms
depth-first-search
+
–
1
votes
1
answer
1581
MadeEasy Test Series: Algorithms - Minimum Spanning Trees
dileswar sahu
772
views
dileswar sahu
asked
Jul 19, 2016
Algorithms
made-easy-test-series
algorithms
minimum-spanning-tree
+
–
2
votes
2
answers
1582
MadeEasy Test Series: Programming & DS - Programming In C
what is the precedence of ^ , & , | operator in C? answer 2 program with explanation required. Q1. int i=2,j=2; int k=i^j&1; //what is the k value at the end? Q2. int d=5&4|6;//what is the d value at the end?
what is the precedence of ^ , & , | operator in C? answer 2 program with explanation required.Q1. int i=2,j=2; int k=i^j&1; //what is the k value at the end?Q2. int...
Sourabh Kumar
653
views
Sourabh Kumar
asked
Jul 16, 2016
Programming in C
made-easy-test-series
programming
programming-in-c
+
–
0
votes
4
answers
1583
MadeEasy Test Series: Numerical Ability - Odd One Out
Sourabh Kumar
640
views
Sourabh Kumar
asked
May 21, 2016
Analytical Aptitude
made-easy-test-series
general-aptitude
analytical-aptitude
odd-one
+
–
0
votes
2
answers
1584
MadeEasy Test Series: Theory Of Computation - Identify Class Language
ww^r complement is CSL Is this right or wrong If right please how can we prove
ww^r complement is CSLIs this right or wrongIf right please how can we prove
Sourabh Kumar
736
views
Sourabh Kumar
asked
Apr 23, 2016
Theory of Computation
made-easy-test-series
theory-of-computation
identify-class-language
+
–
0
votes
1
answer
1585
MadeEasy Test Series: Theory Of Computation - Finite Automata
Sourabh Kumar
319
views
Sourabh Kumar
asked
Apr 22, 2016
Theory of Computation
made-easy-test-series
theory-of-computation
finite-automata
+
–
1
votes
3
answers
1586
MadeEasy Test Series: Theory Of Computation - Pushdown Automata
Every cfg may not have equivalent pda T/F
Every cfg may not have equivalent pdaT/F
Sourabh Kumar
1.2k
views
Sourabh Kumar
asked
Apr 22, 2016
Theory of Computation
made-easy-test-series
theory-of-computation
pushdown-automata
+
–
0
votes
1
answer
1587
MadeEasy Test Series: Operating System - Disk Scheduling
Consider the following disk request sequence for a disk with 100 tracks. 98, 183, 37, 122, 14, 124, 65, 67 Head pointer starting at 53 (current position of R/W heads).Find the number of head movements in cylinders using SSTF scheduling.
Consider the following disk request sequence for a disk with 100 tracks.98, 183, 37, 122, 14, 124, 65, 67Head pointer starting at 53 (current position of R/W heads).Find ...
Jitendra Verma
3.4k
views
Jitendra Verma
asked
Mar 16, 2016
Operating System
made-easy-test-series
operating-system
disk-scheduling
+
–
0
votes
2
answers
1588
MadeEasy Test Series: Operating System - Disk Scheduling
Consider the following disk request sequence for a disk with 100 tracks. 98, 183, 37, 122, 14, 124, 65, 65, 67 Head pointer starting at 53 (current position of R/W heads) and moving in left direction.Find the number of head movements in cylinders using SCAN scheduling.
Consider the following disk request sequence for a disk with 100 tracks.98, 183, 37, 122, 14, 124, 65, 65, 67Head pointer starting at 53 (current position of R/W heads) a...
Jitendra Verma
2.3k
views
Jitendra Verma
asked
Mar 16, 2016
Operating System
made-easy-test-series
operating-system
disk-scheduling
+
–
2
votes
2
answers
1589
MadeEasy Test Series: Operating System - Process Synchronization
Description of Peterson's Algorithm & also for which problem it is used to solve (1) deadlock (2) mutual exclusion (3) Thrashing (4) Paging.
Description of Peterson's Algorithm & also for which problem it is used to solve(1) deadlock(2) mutual exclusion(3) Thrashing(4) Paging.
Jitendra Verma
3.1k
views
Jitendra Verma
asked
Mar 11, 2016
Operating System
made-easy-test-series
operating-system
process-synchronization
+
–
6
votes
1
answer
1590
MadeEasy Test Series: Databases - B Tree
What is the minimum levels of B+ tree index required for 5000 keys and order of B+ tree node (P) is 10. (Assume P is the max pointer possible to store in B+ tree node) My answer was 3. With: Keys <= (Internal Order)^levels * (Leaf Order) i.e., 10^3 * 9 = 9000 >= 5000 .. So 3 levels req. But given answer is 4.
What is the minimum levels of B+ tree index required for 5000 keys and order of B+ tree node (P) is 10. (Assume P is the max pointer possible to store in B+ tree node) My...
Tushar Shinde
4.2k
views
Tushar Shinde
asked
Feb 4, 2016
Databases
made-easy-test-series
databases
b-tree
+
–
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