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Recent questions tagged memory-management

5 votes
3 answers
1
GATE CSE 2021 Set 2 | Question: 48
Consider a three-level page table to translate a $39$-bit virtual address to a physical address as shown below: The page size is $\text{4 KB}$ = ($\text{1KB}$ $=2^{10}$ bytes) and page table entry size at every level is $8$ bytes. ... $P$ across all levels is _________ $\text{KB}$.
Consider a three-level page table to translate a $39$-bit virtual address to a physical address as shown below: The page size is $\text{4 KB}$ = ($\text{1KB}$ $=2^{10}$ bytes) and page table entry size at every level is $8$ bytes. A process $P$ is ... $\text{2GB}$ of physical memory. The minimum amount of memory required for the page table of $P$ across all levels is _________ $\text{KB}$.
asked Feb 18 in Operating System Arjun 1k views
2 votes
3 answers
2
NIELIT 2016 MAR Scientist C - Section C: 8
If there are $32$ segments, each of size $1$ K byte, then the logical address should have $13 \text{ bits}$ $14 \text{ bits}$ $15 \text{ bits}$ $16 \text{ bits}$
If there are $32$ segments, each of size $1$ K byte, then the logical address should have $13 \text{ bits}$ $14 \text{ bits}$ $15 \text{ bits}$ $16 \text{ bits}$
asked Apr 2, 2020 in Operating System Lakshman Patel RJIT 445 views
2 votes
2 answers
5
NIELIT 2017 OCT Scientific Assistant A (CS) - Section B: 4
If a processor has $32$-bit virtual address, $28$-bit physical address, $2$ kb pages. How many bits are required for the virtual, physical page number? $17,21$ $21,17$ $6,10$ None
If a processor has $32$-bit virtual address, $28$-bit physical address, $2$ kb pages. How many bits are required for the virtual, physical page number? $17,21$ $21,17$ $6,10$ None
asked Apr 1, 2020 in Operating System Lakshman Patel RJIT 254 views
1 vote
1 answer
6
NIELIT 2016 DEC Scientist B (IT) - Section B: 51
Copying a process from memory to disk to allow space for other processes is called: Swapping Demand Paging Deadlock Page Fault
Copying a process from memory to disk to allow space for other processes is called: Swapping Demand Paging Deadlock Page Fault
asked Mar 31, 2020 in Operating System Lakshman Patel RJIT 391 views
2 votes
2 answers
7
NIELIT 2017 July Scientist B (CS) - Section B: 32
A CPU generates $32$-bit virtual addresses. The page size is $4$ KB. The processor has a Translation Look-aside Buffer (TLB) which can hold a total of $128$ page table entries and is $4$-way set associative. The minimum size of the TLB tag is $\text{11 bits}$ $\text{13 bits}$ $\text{15 bits}$ $\text{20 bits}$
A CPU generates $32$-bit virtual addresses. The page size is $4$ KB. The processor has a Translation Look-aside Buffer (TLB) which can hold a total of $128$ page table entries and is $4$-way set associative. The minimum size of the TLB tag is $\text{11 bits}$ $\text{13 bits}$ $\text{15 bits}$ $\text{20 bits}$
asked Mar 30, 2020 in Operating System Lakshman Patel RJIT 342 views
0 votes
4 answers
8
NIELIT 2017 DEC Scientist B - Section B: 16
Which of the following is added to the page table in order to track whether a page of cache has been modified since it was read from the memory? Reference bit Dirty bit Tag bit Valid bit
Which of the following is added to the page table in order to track whether a page of cache has been modified since it was read from the memory? Reference bit Dirty bit Tag bit Valid bit
asked Mar 30, 2020 in Operating System Lakshman Patel RJIT 977 views
1 vote
3 answers
9
UGCNET-Jan2017-III: 49
A memory management system has $64$ pages with $512$ bytes page size. Physical memory consists of $32$ page frames Number of bits required in logical and physical address are respectively: $14$ and $15$ $14$ and $29$ $15$ and $14$ $16$ and $32$
A memory management system has $64$ pages with $512$ bytes page size. Physical memory consists of $32$ page frames Number of bits required in logical and physical address are respectively: $14$ and $15$ $14$ and $29$ $15$ and $14$ $16$ and $32$
asked Mar 24, 2020 in Operating System jothee 432 views
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