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Recent questions tagged multilevel-cache

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1
Cache Mapping
In a 2 level hierarchy, the cache has an access time of 15 ns and the main memory has an access time of 110 ns, the hit rate of the cache is 90%. If the block size of the cache is 16 Bytes, then average memory access time including miss penalty is?
In a 2 level hierarchy, the cache has an access time of 15 ns and the main memory has an access time of 110 ns, the hit rate of the cache is 90%. If the block size of the...
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2 votes
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2
cache miss question
In $T_{Read Avg}$, shouldn’t it be $T_{Read Avg}$ = (10*0.9) + 0.1*(10+100), because it must be checking the cache in case of cache miss too, right?
In $T_{Read Avg}$, shouldn’t it be $T_{Read Avg}$ = (10*0.9) + 0.1*(10+100), because it must be checking the cache in case of cache miss too, right?
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8
CO madeeasy 2019 Multi level cache
please explain how hit ratio of L2 is taken as 0.5? instead of 0.9 as 10 misses are mentioned is it like as 20 misses at levle 1 out of which only 10 missed at level 2, so 10 out of 20 (and not 100) hence 0.5?
please explain how hit ratio of L2 is taken as 0.5? instead of 0.9 as 10 misses are mentionedis it like as 20 misses at levle 1 out of which only 10 missed at level 2, so...
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15
Gate forum Exam
In two level cache first level cache minimizes cache miss ratio , second level minimizes cache hit ratio . Explain .
In two level cache first level cache minimizes cache miss ratio , second level minimizes cache hit ratio . Explain .
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–1 votes
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22
Carl Hamacher Cache Memory
What should be correct answer to this question? In solution it's option A in Carl hamacher text book it's B ? I am confused please help
What should be correct answer to this question?In solution it's option A in Carl hamacher text book it's B ? I am confused please help
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0 votes
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26
Comp.Architecture-3
My work: $1+0.1*5+0.05*50=4ns$ Now please give me reasoning about : missing in $L1$ i will access $L2$ and i did that now When i am missing in $L2$ isn`t this obvious that i have actually missed in $L1 $ or should i mention it by $0.05*0.1*50$ Thanks!
My work: $1+0.1*5+0.05*50=4ns$Now please give me reasoning about : missing in $L1$ i will access $L2$ and i did that now When i am missing in $L2$ isn t this obvious tha...
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27
co cache memory
if there is a miss in cache and hit in mm what is access time 60ns or 60+20=80ns. how is the statement " reference started again" related to the meaning of the question?
if there is a miss in cache and hit in mm what is access time 60ns or 60+20=80ns.how is the statement " reference started again" related to the meaning of the question?
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