Pointer arithmetic
What is the output of the following ? int main() { int arr[2][3][2]={1,2,3,4,5,6,7,8,9,10,11,12}; printf("%d%d", a[1]-a[0], a[1][0]-a[0][0]); return 0; }
What is the output of the following ?int main(){int arr [3] ={1,2,3,4,5,6,7,8,9,10,11,12};printf("%d%d", a -a[0], a [0]-a[0][0]);return 0;}