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Recent questions tagged pointers

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183
mock test
#include <stdio.h> #define R 10 #define C 20 int main() { int (*p)[R][C]; printf("%d", sizeof(*p)); getchar(); return 0; } a 200 B 4 c 800 D 80
#include <stdio.h>#define R 10#define C 20int main(){ int (*p)[R][C]; printf("%d", sizeof(*p)); getchar(); return 0;}a200B4c800D80
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3 answers
184
NET nov-17 paper-2 Q11
ptrdata is a pointer to a data type . The expression *ptrdata++ is evaluated as ( in C++) a) *(ptrdata++) b) (*ptrdata)++ c) *(ptrdata)++ d) depends on compiler
ptrdata is a pointer to a data type . The expression *ptrdata++ is evaluated as ( in C++) a) *(ptrdata++) b) (*ptrdata)++c) *(ptrdata)++ d) depends on compiler
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1 votes
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185
what will the value printed by code
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188
[Programming] What is the output of the following programme ?
#include <stdio.h> int main() { int a[] = {50, 60, 10, 30, 40, 20 }; int *b[] = {a+3, a+4, a, a+2, a+1, a+5 }; int **c = b; c++; printf("%u, %u, %u\n", c-b, *c - a, **c); return 0; }
#include <stdio.h>int main(){ int a[] = {50, 60, 10, 30, 40, 20 }; int *b[] = {a+3, a+4, a, a+2, a+1, a+5 }; int c = b; c++; printf("%u, %u, %u\n", c-b, *...
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189
Pointers
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1 votes
3 answers
190
output
#include<stdio.h> int main() { int array[2][3]={5,10,15,20,25,30}; int (*ptr)[2][3]=&array; printf("%d\t",**(*ptr+1)); } can someone explain how is it "20"??
#include<stdio.h>int main() {int array [3]={5,10,15,20,25,30};int (*ptr) [3]=&array;printf("%d\t", (*ptr+1));}can someone explain how is it "20"??
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1 votes
2 answers
191
pointer
#include<stdio.h> int main() { int const * i= 5; printf("%d\n", ++(*i)); } a. 5 b. garbage value c. compilation error d.runtime error
#include<stdio.h>int main() { int const * i= 5; printf("%d\n", ++(*i));} a. 5b. garbage valuec. compilation errord.runtime error
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192
c programming
output with explanation ?
output with explanation ?
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1 answer
193
programming
main() { int * ptr =(int *) malloc (5*sizeof(int)); for(i=0;i<5;i++) *(ptr+i)=i; pf("%d",*ptr++); pf("%d",(*ptr)++); pf("%d",*ptr1); pf("%d",*++ptr); pf("%d",++*ptr); }
main() { int * ptr =(int *) malloc (5*sizeof(int)); for(i=0;i<5;i++) *(ptr+i)=i; pf("%d",*ptr++); pf("%d",(*ptr)++); pf("%d",*ptr1); pf("%d",*++ptr); pf("%d",++*ptr); }
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3 answers
194
Programming in C
#include <stdio.h> void f(int,int); int main(void){ int a = 5; f(a,a); printf("%d",a); } void f(int x, int y){ x--; y=y+15; } If copy-restore is used, then what will be the value of print(a)?
#include <stdio.h void f(int,int); int main(void){ int a = 5; f(a,a); printf("%d",a); } void f(int x, int y){ x ; y=y+15; }If copy-restore is used, then what will be the ...
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1 votes
1 answer
195
C Programming
Explain the Output of the Following C Code: int main() { char s[]={'g','a','t','e','c','s'}; char r[]={'G','A','T','E','C','S'}; char *p,*q,*str1,*str2; p=&s[4]; q= ... +*str1++ + ++*str2++-32); printf("%c",3[s]+++*(s+2)-2[r]+++*q-++*r-32); return 0; }
Explain the Output of the Following C Code: int main() { char s[]={'g','a','t','e','c','s'}; char r[]={'G','A','T','E','C','S'}; char *p,*q,*str1,*str2; p=&s[4]; q=&r ; s...
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2 answers
196
pointer airthmatic
we can subtract 2 pointer address then why we can't perform operations like addition, multiplication or division on pointer address??? any specific reason?
we can subtract 2 pointer address then why we can't perform operations like addition, multiplication or division on pointer address???any specific reason?
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1 votes
1 answer
197
Programming in C
#include <stdio.h> int main(void){ int i=511; char *p = (char *)&i; printf("%d", *p); } OK so why take 2's complement and not simple binary number? Means, why is C giving -1 and not 255?
#include <stdio.h int main(void){ int i=511; char *p = (char *)&i; printf("%d", *p); }OK so why take 2's complement and not simple binary number? Means, why is C giving -...
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3 votes
0 answers
198
pointer_arithmetic
Illustration of this piece of code :
Illustration of this piece of code :
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3 votes
0 answers
199
pointer
#include<stdio.h> int main() { int a = 10; void *ptr = &a; printf("%d", sizeof(ptr)); return 0; } output =8 how ?if we know size of pointer is already machine dependent then in this case ptr is referring a address of int then how output 8 ?
#include<stdio.h>int main(){ int a = 10; void *ptr = &a; printf("%d", sizeof(ptr)); return 0;}output =8how ?if we know size of pointer is already machine depe...
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1 votes
0 answers
200
pointer
pls explain why option d is wrong ?
pls explain why option d is wrong ?
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1 votes
1 answer
203
Pointer Casting
Analyze what is happening and why? int *ptr=(int*)0X12341230; int *ptr2=((int*)(((char*)ptr)+1)); char *ptr=(char*) 0X12341230; void *ptr2=ptr+1;
Analyze what is happening and why?int *ptr=(int*)0X12341230; int *ptr2=((int*)(((char*)ptr)+1));char *ptr=(char*) 0X12341230; void *ptr2=ptr+1;
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1 votes
1 answer
204
#dennis
#include<stdio.h> void print1(void){ static int x=10; x+=5; printf("%d",x); } void print2(void){ static int x; x=10; x+=5; printf("%d",x); } int main(){ print1(); print1(); print2(); print2(); getch(); return 0; } please let me know how print1 and print2 is working?
#include<stdio.h>void print1(void){static int x=10;x+=5;printf("%d",x);}void print2(void){static int x;x=10;x+=5;printf("%d",x);}int main(){print1();print1();print2();pri...
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1 votes
0 answers
206
C programming
#include <stdio.h> int main() { int i =258; int *iptr = &i; printf("%d%d",*((char*)iptr),*((char*)iptr+1)); return 0; } (a)2,1 (b)2,5 (c)1, 2 (d)5,2 I am getting (a) as output sh-4.2$ gcc -o main *.c sh-4.2$ main 21 Can anybody explain that how we got that? Thanks :)
#include <stdio.h int main() { int i =258; int *iptr = &i; printf("%d%d",*((char*)iptr),*((char*)iptr+1)); return 0; }(a)2,1 (b)2,5(c)1, 2 (d)5,2I am getting (a) as out...
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5 votes
1 answer
207
pointers
char ** array [12][12][12] what is valid initialization of p ? ANS = char * * * * *p=array; but i feel it should be char * * * * * *p =array; please help
char array [12][12][12]what is valid initialization of p ?ANS = char * * * * *p=array;but i feel it should be char * * * * * *p =array;please help
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2 votes
3 answers
209
Pointers
One of the disadvantage of pass by reference is that the called function may inadvertently corrupt the caller's data. This can be avoided by : a) declaring the actual parameters constant b) declaring the formal parameters constant c) passing pointers d) None of these
One of the disadvantage of pass by reference is that the called function may inadvertently corrupt the caller's data. This can be avoided by :a) declaring the actual para...
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1 votes
1 answer
210
i read string constant cannot be modified here it gets modified whyyyy
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