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Recent questions tagged sizeof-operator

1 votes
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1
sizeof
#include <stdio.h> int main() { int a = 1; char d[] = "ab"; printf("%d", sizeof(a+d)); return 0; } Explain the Output
#include <stdio.h int main() { int a = 1; char d[] = "ab"; printf("%d", sizeof(a+d)); return 0; }Explain the Output
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1 votes
1 answer
2
How does sizeof() operator work for multidimensional array ?
If I have an array : int a[2][3][4] ; How to evaluate below Outputs ? 1. sizeof(*a) 2.sizeof(**a) 3. sizeof(a) Please explain precisely .
If I have an array :int a [3][4] ; How to evaluate below Outputs ? 1. sizeof(*a) 2.sizeof( a) 3. sizeof(a) Please explain precisely .
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1 votes
2 answers
3
array sizeof
#include<stdio.h> int main() { char *s="\123456789\n"; printf("%d", sizeof(s)); return 0; } why this piece of code gives output $8$ please explain. thanx
#include<stdio.h int main() { char *s="\123456789\n"; printf("%d", sizeof(s)); return 0; }why this piece of code gives output $8$please explain. thanx
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1 answer
4
Size of operator
#include<stdio.h> int main(void) { printf("bytes occupied by '7' = %d\n", sizeof('7')); printf("bytes occupied by 7 = %d\n", sizeof(7)); printf("bytes occupied by 7.0 = %d\n", sizeof(7.0)); return 0; }
#include<stdio.h int main(void) { printf("bytes occupied by '7' = %d\n", sizeof('7')); printf("bytes occupied by 7 = %d\n", sizeof(7)); printf("bytes occupied by 7.0 = %d...
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