Recent questions tagged triangles

2 votes
1 answer
9
In the figure shown below, the circle has diameter $5$. Moreover, $AB$ is parallel to $DE.$ If $DE=3$ and $AB=6,$ what is the area of triangle $ABC?$
0 votes
1 answer
10
If a square of side $a$ and an equilateral triangle of side $b$ are inscribed in a circle then $a/b$ equals$\sqrt{2/3}$$\sqrt{3/2}$$3/ \sqrt{2}$$\sqrt{2}/3$
1 votes
1 answer
11
The medians $AD$ and $BE$ of the triangle with vertices $A(0,b)$, $B(0,0)$ and $C(a,0)$ are mutually perpendicular if$b=\sqrt{2}a$$b=\pm \sqrt{2}b$$b= – \sqrt{2}a$$b=a$...
0 votes
0 answers
12
Which of the following relations is true for the following figure?$b^2 = c(c+a)$$c^2 = a(a+b)$$a^2=b(b+c)$All of these
0 votes
1 answer
13
The medians $AD$ and $BE$ of the triangle with vertices $A(0,b),B(0,0)$ and $C(a,0)$ are mutually perpendicular if$b=\sqrt{2}a$$a=\pm\sqrt{2}b$$b=-\sqrt{2}a$$b=a$
0 votes
0 answers
14
If in a $\triangle ABC,\angle B=\dfrac{2\pi}{3},$ then $\cos A+\cos C$ lies in$\left[\:-\sqrt{3},\sqrt{3}\:\right]$$\left(\:-\sqrt{3},\sqrt{3}\:\right]$$\left(\:\frac{3}{...
0 votes
0 answers
15
Which of the following relations is true for the following figure?$b^{2}=c(c+a)$$c^{2}=a(a+b)$$a^{2}=b(b+c)$All of these
0 votes
1 answer
16
If $a,b,c$ are the sides of a triangle such that $a:b:c=1: \sqrt{3}:2$, then $A:B:C$ (where $A,B,C$ are the angles opposite to the sides of $a,b,c$ respectively) is$3:2:1...
0 votes
1 answer
17
Let the sides opposite to the angles $A,B,C$ in a triangle $ABC$ be represented by $a,b,c$ respectively. If $(c+a+b)(a+b-c)=ab,$ then the angle $C$ is$\frac{\pi}{6}$$\fra...
1 votes
2 answers
19
1 votes
2 answers
21
Which of the triangles is an isosceles triangle having the three angles :$40^{\circ},50^{\circ},90^{\circ}$$30^{\circ},60^{\circ},90^{\circ}$$45^{\circ},45^{\circ},90^{\c...
1 votes
2 answers
22
29 votes
4 answers
23
In the figure below, $\angle DEC + \angle BFC$ is equal to _____$\angle BCD - \angle BAD$$\angle BAD + \angle BCF$$\angle BAD + \angle BCD$$\angle CBA + \angle ADC$
6 votes
3 answers
24
In the given figure angle $Q$ is a right angle, $PS:QS = 3:1, RT:QT = 5:2$ and $PU:UR = 1:1. $ If area of triangle $QTS$ is $20cm^{2},$ then the area of triangle $PQR$ in...
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