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Answers by 1997_satya
0
votes
1
MADE EASY
Consider the counter circuit and propagation delay table shown below: (Assume all the devices are ideal except for some propagation delay). What is the maximum clock frequency that can be applied to the above counter A) 125 kHz B)100 kHz C)200 kHz D)142.85 kHz
Consider the counter circuit and propagation delay table shown below:(Assume all the devices are ideal except for some propagation delay).What is the maximum clock freque...
491
views
answered
Jan 27, 2019
0
votes
2
made easy test
Given below are 4 functions $999999n$ $0.99999 n logn$ $1.000001^{n}$ $n^{2}$ The increasing order of the above functions in terms of their asymptotic complexity is?
Given below are 4 functions$999999n$$0.99999 n logn$$1.000001^{n}$$n^{2}$The increasing order of the above functions in terms of their asymptotic complexity is?
588
views
answered
Jan 10, 2019
Algorithms
algorithms
asymptotic-notation
made-easy-test-series
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–
0
votes
3
Digital logic
plz tell how it take common B’ and B
plz tell how it take common B’ and B
307
views
answered
Jan 10, 2019
Digital Logic
digital-logic
multiplexer
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–
5
votes
4
MadeEasy Test Series 2019: Computer Networks - Congestion Control
here TOTAL 2000 segments need to be sent, and after x RTT, it will send 2001 segments but for total we shall take count of addition of all the previous also na?
here TOTAL 2000 segments need to be sent, and after x RTT, it will send 2001 segments but for total we shall take count of addition of all the previous also na?
930
views
answered
Jan 10, 2019
Computer Networks
computer-networks
congestion-control
tcp
transport-layer
made-easy-test-series
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–
2
votes
5
GATE2017 CE-2: GA-9
Budhan covers a distance of $19$ km in $2$ hours by cycling one fourth of the time and walking the rest. The next day he cycles (at the same speed as before) for half the time and walks the rest (at the same speed as before) and covers $26$ km in $2$ hours. The speed in km/h at which Budhan walk is $1$ $4$ $5$ $6$
Budhan covers a distance of $19$ km in $2$ hours by cycling one fourth of the time and walking the rest. The next day he cycles (at the same speed as before) for half the...
2.8k
views
answered
Jan 9, 2019
Quantitative Aptitude
gate2017-ce-2
speed-time-distance
quantitative-aptitude
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–
0
votes
6
MadeEasy Subject Test 2019: Theory Of Computation - Regular Expressions
the length of the shortest string which is not present in the regular expression 1*(0+10)*1* is?
the length of the shortest string which is not present in the regular expression 1*(0+10)*1* is?
635
views
answered
Dec 22, 2018
Theory of Computation
made-easy-test-series
theory-of-computation
regular-expression
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0
votes
7
Two level of cache
Consider a two level cache system. For 100 memory references 20 misses in 1st level cache,10 misses in second level cache. Miss penalty from second level to memory is 40 cycles. if Total average = 7.6 cycles, then hit time of second level cache ? Assume hit time of second level cache is two times the first level cache? Ans. 4
Consider a two level cache system. For 100 memory references 20 misses in 1st level cache,10 misses in second level cache. Miss penalty from second level to memory is 40 ...
5.7k
views
answered
Oct 3, 2018
CO and Architecture
co-and-architecture
cache-memory
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1
votes
8
#OS Process Synchronisation GATE2015 Self User Doubt
Original Question - https://gateoverflow.in/8405/gate2015-3-10 Answer is A) Yes, there's no ME (That's fine) Also there's no Deadlock, but for no deadlock, can we give reason as - There's no deadlock, because ... and Y on VarQ. So, there's no dependency there. And hence No deadlock? Is this reasoning for deadlock valid?
Original Question - https://gateoverflow.in/8405/gate2015-3-10 Answer is A) Yes, there's no ME (That's fine) Also there's no Deadlock, but for no deadlock, can we give re...
914
views
answered
Aug 20, 2018
Operating System
operating-system
usermod
users
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