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1 votes
0 answers
1261
NIELIT 2018-20
The general solution of the differential equation $\frac{dy}{dx} = (1+y^2)(e^{-x^2}-2x \tan^{-1} y)$ is: $e^{x^2} \tan^{-1} y = x+c$ $e^{-x^2} \tan^y = x+c$ $e^x \tan y = x^2+c$ $e^{-x} \tan^{-1} y = x^3+c$
The general solution of the differential equation $\frac{dy}{dx} = (1+y^2)(e^{-x^2}-2x \tan^{-1} y)$ is:$e^{x^2} \tan^{-1} y = x+c$$e^{-x^2} \tan^y = x+c$$e^x \tan y = x^...
2 votes
1 answer
1262
NIELIT 2018-21
The value of $p$ such that the vector $\begin{bmatrix} 1 \\ 2 \\ 3 \end{bmatrix}$ is an eigen vector of the matrix $\begin{bmatrix} 4 & 1 & 2 \\ p & 2 & 1 \\ 14 & -4 & 10 \end{bmatrix}$ is $15$ $16$ $17$ $18$
The value of $p$ such that the vector $\begin{bmatrix} 1 \\ 2 \\ 3 \end{bmatrix}$ is an eigen vector of the matrix $\begin{bmatrix} 4 & 1 & 2 \\ p & 2 & 1 \\ 14 & -4 & 10...
1 votes
1 answer
1263
NIELIT 2018-22
While solving the differential equation $\frac{d^2 y}{dx^2} +4y = \tan 2x$ by the method of variation of parameters, then value of Wronskion (W) is: $1$ $2$ $3$ $4$
While solving the differential equation $\frac{d^2 y}{dx^2} +4y = \tan 2x$ by the method of variation of parameters, then value of Wronskion (W) is:$1$$2$$3$$4$
2 votes
0 answers
1266
NIELIT 2018-25
The general solution of the partial differential equation $(D^2-D’^2-2D+2D’)Z=0$ where $D= \frac{\partial}{\partial x}$ and $D’=\frac{\partial}{\partial y}$: $f(y+x)+e^{2x}g(y-x)$ $e^{2x} f(y+x)+g(y-x)$ $e^{-2x} f(y+x)+g(y-x)$ $f(y+x)+e^{-2x}g(y-x)$
The general solution of the partial differential equation $(D^2-D’^2-2D+2D’)Z=0$ where $D= \frac{\partial}{\partial x}$ and $D’=\frac{\partial}{\partial y}$:$f(y+x)...
2 votes
0 answers
1267
NIELIT 2018-26
If $P(A \cap B) = \frac{1}{2}, \: P(\overline{A} \cap \overline{B}) = \frac{1}{2}$ and $2P(A)=P(B)=p$, then the value of $p$ is given by: $\frac{1}{4}$ $\frac{1}{2}$ $\frac{1}{3}$ $\frac{2}{3}$
If $P(A \cap B) = \frac{1}{2}, \: P(\overline{A} \cap \overline{B}) = \frac{1}{2}$ and $2P(A)=P(B)=p$, then the value of $p$ is given by:$\frac{1}{4}$$\frac{1}{2}$$\frac{...
2 votes
1 answer
1268
NIELIT 2018-27
The following vectors $(1, 9, 9, 8), (2, 0, 0, 8), (2, 0, 0, 3)$ are Linearly dependent Linearly independent Constant None of these
The following vectors $(1, 9, 9, 8), (2, 0, 0, 8), (2, 0, 0, 3)$ areLinearly dependentLinearly independentConstantNone of these
1 votes
1 answer
1269
NIELIT 2018-28
For the function $(z) = \frac{1}{z^2(e^z-1)}, z=0$ is a pole of order: $1$ $2$ $3$ None of these
For the function $(z) = \frac{1}{z^2(e^z-1)}, z=0$ is a pole of order:$1$$2$$3$None of these
1 votes
1 answer
1270
NIELIT 2018-29
Using Green’s theorem in plane, evaluate $\int_c (2x-y) dx + (x+y)dy$, where $c$ is the circle $x^2+y^2=4$ in the plane: $2 \pi$ $4 \pi$ $-4 \pi$ $8 \pi$
Using Green’s theorem in plane, evaluate $\int_c (2x-y) dx + (x+y)dy$, where $c$ is the circle $x^2+y^2=4$ in the plane:$2 \pi$$4 \pi$$-4 \pi$$8 \pi$
3 votes
1 answer
1271
NIELIT 2018-30
If $C$ is a non-singular matrix and $B=C \begin{bmatrix} 0 & x & y \\ 0 & 0 & x \\ 0 & 0 & 0 \end{bmatrix} C^{-1}$ then: $B^2=I$ $B^2 = \text{Null Matrix}$ $B^3=I$ $B^3 = \text{Null Matrix}$
If $C$ is a non-singular matrix and $B=C \begin{bmatrix} 0 & x & y \\ 0 & 0 & x \\ 0 & 0 & 0 \end{bmatrix} C^{-1}$ then:$B^2=I$$B^2 = \text{Null Matrix}$$B^3=I$$B^3 = \te...
3 votes
3 answers
1272
NIELIT 2018-31
Identify the subnet mask for the given direct broadcast address of subnet is $201.15.16.31$ $255.255.192.192$ $255.255.255.198$ $255.255.255.240$ $255.255.257.240$
Identify the subnet mask for the given direct broadcast address of subnet is $201.15.16.31$$255.255.192.192$$255.255.255.198$$255.255.255.240$$255.255.257.240$
1 votes
3 answers
1273
NIELIT 2018-32
The context free grammar $S \rightarrow aSb \mid bSa \mid \epsilon$ generates: Equal number of a’s and b’s Unequal number of a’s and b’s Any number of a’s followed by any number of b’s Any number of b’s followed by any number of a’s
The context free grammar $S \rightarrow aSb \mid bSa \mid \epsilon$ generates:Equal number of a’s and b’sUnequal number of a’s and b’sAny number of a’s followed...
1 votes
3 answers
1274
NIELIT 2018-33
The language $\{ W^a X^b Y^{a+b} \mid a, b, >1\}$ is Regular Context-free but not regular Context sensitive but not context free Type$=0$ but not context sensitive
The language $\{ W^a X^b Y^{a+b} \mid a, b, >1\}$ isRegularContext-free but not regularContext sensitive but not context freeType$=0$ but not context sensitive
1 votes
2 answers
1275
NIELIT 2018-34
Identify the true statement from the given statements: Number of child pointers in a B/B+ tree node is always equal to number of keys in it plus one B/B+ tree is defined by a term minimum degree. And minimum degree depends on hard disk block size, key and address size (1) (1) and (2) (2) None of these
Identify the true statement from the given statements:Number of child pointers in a B/B+ tree node is always equal to number of keys in it plus oneB/B+ tree is defined by...
0 votes
2 answers
1276
NIELIT 2018-35
Baud rate measures the number of ____ transmitted per second Symbols Bits Byte None of these
Baud rate measures the number of ____ transmitted per secondSymbolsBitsByteNone of these
2 votes
3 answers
1277
NIELIT 2018-36
______ is NOT a part of the ACID properties Inconsistency Consistency Atomicity Isolation
______ is NOT a part of the ACID propertiesInconsistencyConsistencyAtomicityIsolation
1 votes
3 answers
1278
NIELIT 2018-37
The smallest element that can be found in time ____ in a binary max heap. $O(n \log n)$ $O( \log n)$ $O(n)$ $O(n^2)$
The smallest element that can be found in time ____ in a binary max heap.$O(n \log n)$$O( \log n)$$O(n)$$O(n^2)$
0 votes
1 answer
1279
NIELIT 2018-38
Find the effective access time for the memory for the given data. Page fault service time $=8$ ms Average memory access time $=20$ ns One page fault is generated for every memory access $=10^6$ $29$ ns $33$ ns $28$ ns $30$ ns
Find the effective access time for the memory for the given data.Page fault service time $=8$ msAverage memory access time $=20$ nsOne page fault is generated for every m...
1 votes
3 answers
1280
NIELIT 2018-39
A RAM chip has a capacity of $1024$ words of $8$ bits each $(1K \times 8)$. The number of $2 \times 4$ decoders with enable line needed to construct a $32 K \times 8$ RAM from $1K \times 8$ RAM is $4$ $5$ $6$ $7$
A RAM chip has a capacity of $1024$ words of $8$ bits each $(1K \times 8)$. The number of $2 \times 4$ decoders with enable line needed to construct a $32 K \times 8$ RAM...
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