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Recent activity by Hopealways
1
answer
1
Expected iit
My marks for gate cse 2019 as per GO is 70. This year the trend totally changed. Previous year with a marks of 70 one would get into IITB easily, rank around 50. But this year i guess it will be hard to get into IITH with 70 marks. What IIT can I expect?
My marks for gate cse 2019 as per GO is 70. This year the trend totally changed. Previous year with a marks of 70 one would get into IITB easily, rank around 50.But this ...
709
views
asked
Feb 12, 2019
Written Exam
general
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–
0
answers
2
Digital Logic - Min Sum Of Products Form
What is the minimum SOP expression for the following f(a,b,c,d) = Σm(8, 10, 11, 12, 13, 15) + Σd(7, 9 , 14)? I’m getting only “a” as the answer, but the answer given is “a + bcd”. My doubt – the “Dont care term” generating the expression “bcd” is NOT necessary, and it is NOT considered as an Essential Prime Implicant. Please correct if I’m wrong
What is the minimum SOP expression for the followingf(a,b,c,d) = Σm(8, 10, 11, 12, 13, 15) + Σd(7, 9 , 14)?I’m getting only “a” as the answer, but the answer give...
487
views
commented
Dec 31, 2018
Digital Logic
digital-logic
min-sum-of-products-form
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1
answer
3
The maximum number of distinct subwords of the word "AXIOMATIZABLE" is: a)183 b) 111 c)92 d)88
5.1k
views
commented
Dec 16, 2018
Combinatory
combinatory
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–
7
answers
4
GATE CSE 2015 Set 2 | Question: 29
Consider the intermediate code given below. (1) i=1 (2) j=1 (3) t1 = 5 * i (4) t2 = t1 + j (5) t3 = 4 * t2 (6) t4 = t3 (7) a[t4] = -1 (8) j = j + 1 (9) if j <= 5 goto (3) (10) i = i +1 (11) if i < 5 goto (2) The number of nodes and edges in control-flow-graph constructed for the above code, respectively, are $5$ and $7$ $6$ and $7$ $5$ and $5$ $7$ and $8$
Consider the intermediate code given below.(1) i=1 (2) j=1 (3) t1 = 5 * i (4) t2 = t1 + j (5) t3 = 4 * t2 (6) t4 = t3 (7) a[t4] = -1 (8) j = j + 1 (9) if j <= 5 goto (3) ...
25.8k
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commented
Dec 1, 2018
Compiler Design
gatecse-2015-set2
compiler-design
intermediate-code
normal
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0
answers
5
MadeEasy Subject Test 2019: Operating System - Process Synchronization
In these type of questions “Will we NOT consider CONTEXT SWITCHING unless mentioned???” If context switching is ALLOWED, minimum value will be 8...Correct me if I’m wrong.
In these type of questions “Will we NOT consider CONTEXT SWITCHING unless mentioned???”If context switching is ALLOWED, minimum value will be 8...Correct me if I’m ...
445
views
commented
Dec 1, 2018
Operating System
made-easy-test-series
operating-system
process-synchronization
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–
0
answers
6
MadeEasy Test Series: Compiler Design - Parsing
Why ε is not shown in First(S). First(s) does contain ε . And please help me figure out which grammar is this? According to me it is NOT LL(1) (since it is left factored), NOT LR(0) (Since the Item 0 has a R-R conflict), NOT SLR(1) (The item 0 has a RR conflict since Follow(X) = Follow(Y) = {a,b} correct me If i'm wrong
Why ε is not shown in First(S). First(s) does contain ε . And please help me figure out which grammar is this?According to me it is NOT LL(1) (since it is left factore...
1.4k
views
commented
Nov 25, 2018
Compiler Design
made-easy-test-series
compiler-design
parsing
ll-parser
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1
answer
7
3 address code
The minimum number of variables required in 3 address code of the given expression are:______ a * b * c + d - a + e * f - g + h Order of precedence: * > + > - ; with * as left associative and +,- as right associative.
The minimum number of variables required in 3 address code of the given expression are:______a * b * c + d - a + e * f - g + hOrder of precedence: * + - ; with * as lef...
4.4k
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answered
Nov 10, 2018
Compiler Design
compiler-design
intermediate-code
three-address-code
numerical-answers
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1
answer
8
Please solve this Q
Consider the relation having tuples 200, 300 and 100 respectively. The number of tuples in relation are ______.
Consider the relation having tuples 200, 300 and 100 respectively. The number of tuples in relation are ______.
776
views
commented
Oct 26, 2018
1
answer
9
madeeasy
A TCP machine is sending windows of 65,535 bytes over 512 Mbps channel that has 20 millisec one way delay. The line efficiency is ________ (upto two decimal places)
A TCP machine is sending windows of 65,535 bytes over 512 Mbps channel that has 20 millisec one way delay. The line efficiency is ________ (upto two decimal places)
654
views
commented
Oct 17, 2018
0
answers
10
After gate
Hi. I appeared in GATE 2018 CSE and my score calculated in gate overflow is 693. Is there a chance of getting a call from any of the top iit's, even from IIT Hyderabad? And what are the chances of NIT's?
Hi.I appeared in GATE 2018 CSE and my score calculated in gate overflow is 693.Is there a chance of getting a call from any of the top iit's, even from IIT Hyderabad?And ...
244
views
asked
Mar 7, 2018
0
answers
11
After Gate
Hi. I appeared in Gate 2018 CSE. My calculated score is 692 as per the score calculator of GO. I wanted to know about my chances in IIT's or NIT's.
Hi.I appeared in Gate 2018 CSE. My calculated score is 692 as per the score calculator of GO.I wanted to know about my chances in IIT's or NIT's.
164
views
asked
Mar 7, 2018
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