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Questions by MiNiPanda

2 votes
1 answer
41
Normalisation
It is said that if a relation is in bcnf then it is also in 3nf. Then why a lossless and non-dependency preserving decomposition qualifies to be in bcnf but not in 3nf. I am not getting it. Please clear my concept.
It is said that if a relation is in bcnf then it is also in 3nf. Then why a lossless and non-dependency preserving decomposition qualifies to be in bcnf but not in 3nf. I...
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