Login
Register
Dark Mode
Brightness
Profile
Edit Profile
Messages
My favorites
My Updates
Logout
Filter
Profile
Wall
Recent activity
All questions
All answers
Exams Taken
All Blogs
Answers by NRN
11
votes
1
GATE CSE 1990 | Question: 3-ix
The number of ways in which $5\; A's, 5\; B's$ and $5\; C's$ can be arranged in a row is: $15!/(5!)^{3}$ $15!$ $\left(\frac{15}{5}\right)$ $15!(5!3!)$.
The number of ways in which $5\; A's, 5\; B's$ and $5\; C's$ can be arranged in a row is:$15!/(5!)^{3}$$15!$$\left(\frac{15}{5}\right)$$15!(5!3!)$.
3.1k
views
answered
Jan 2, 2017
Combinatory
gate1990
normal
combinatory
+
–
Email or Username
Show
Hide
Password
I forgot my password
Remember
Log in
Register