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Questions by Shreya2002
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Made easy Theory of Computation
Which of them are not regular- (a) L={a^m b^n | n>=2023, m<=2023} (b) L={a^n b^m c^l | n=2023, m>2023, l>m} according made easy (b) is the answer but can we do like this- Let L1= {a^n |n=2023} ... ) and so L2 is regular L=L1.L2 (regular lang are closed under concatenation) therefore L is regular.this makes option (b) regular is it right approach ?
Which of them are not regular-(a) L={a^m b^n | n>=2023, m<=2023}(b) L={a^n b^m c^l | n=2023, m>2023, l>m}according made easy (b) is the answer but can we do like this-Let...
308
views
asked
Dec 1, 2022
Theory of Computation
theory-of-computation
regular-language
closure-property
made-easy-test-series
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0
votes
1
answer
2
Madeeasy Algorithm
How to solve this recurrence relation T(n)= T(0.09n) + T(0.91n) + cn where c is constant and T(1)=1 options are-
How to solve this recurrence relationT(n)= T(0.09n) + T(0.91n) + cnwhere c is constant and T(1)=1options are-
1.1k
views
asked
Oct 27, 2022
Algorithms
made-easy-test-series
algorithms
time-complexity
recurrence-relation
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–
1
votes
1
answer
3
Made easy || Database
Consider a relation schema r(A, B, C, D, E, F) and attribute A is element of every candidate key of r. Maximum number of possible candidate keys of r is ________.
Consider a relation schema r(A, B, C, D, E, F) and attribute A is element of every candidate key of r. Maximum number of possible candidate keys of r is ________.
1.5k
views
asked
Aug 9, 2022
Databases
made-easy-test-series
databases
candidate-key
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0
votes
0
answers
4
Database: Minimum number of tuples
Consider a relation schema r(A, B, C). Number of elements in domain of attributes A, B and C are 4, 10 and 17 respectively. “ Minimum ” number of tuples possible in an instance of relation r is ________.
Consider a relation schema r(A, B, C). Number of elements in domain of attributes A, B and C are 4, 10 and 17 respectively. “ Minimum ” number of tuples possible in a...
732
views
asked
Aug 9, 2022
Databases
databases
relations
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–
1
votes
1
answer
5
Made easy || Operating system
Consider a process P running on a system with non-preemptive Kernel design. Consider following actions by P : (i) A blocking system call. (ii) Servicing a timer interrupt. (iii) Exit system call. (iv) Servicing a disk interrupt, that results in another blocked process being marked as ready. Which of the above actions always result in context-switch of P?
Consider a process P running on a system with non-preemptive Kernel design. Consider following actions by P :(i) A blocking system call.(ii) Servicing a timer interrupt.(...
1.6k
views
asked
Aug 5, 2022
Operating System
made-easy-test-series
operating-system
system-call
context-switch
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0
votes
2
answers
6
Made easy || Operating system
While of the following is incorrect? (a) if a system uses preemptive CPU scheduler then deadlock is not possible in system (b) Deadlock state is an unsafe state. (c) If a system has total ordering of all resource types ... disabled) therefore deadlock should not possible in preemptive scheduling then how can this statement could be incorrect. please clarify the doubt
While of the following is incorrect?(a) if a system uses preemptive CPU scheduler then deadlock is not possible in system(b) Deadlock state is an unsafe state.(c) If a sy...
1.3k
views
asked
Aug 5, 2022
Operating System
operating-system
made-easy-test-series
deadlock-prevention-avoidance-detection
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