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Made easy Theory of Computation
Which of them are not regular- (a) L={a^m b^n | n>=2023, m<=2023} (b) L={a^n b^m c^l | n=2023, m>2023, l>m} according made easy (b) is the answer but can we do like this- Let L1= {a^n |n=2023} ... ) and so L2 is regular L=L1.L2 (regular lang are closed under concatenation) therefore L is regular.this makes option (b) regular is it right approach ?
asked
in
Theory of Computation
Dec 2, 2022
165
views
theory-of-computation
regular-language
closure-property
made-easy-test-series
0
votes
1
answer
2
Madeeasy Algorithm
How to solve this recurrence relation T(n)= T(0.09n) + T(0.91n) + cn where c is constant and T(1)=1 options are-
asked
in
Algorithms
Oct 28, 2022
494
views
made-easy-test-series
algorithms
time-complexity
recurrence-relation
1
vote
1
answer
3
Made easy || Database
Consider a relation schema r(A, B, C, D, E, F) and attribute A is element of every candidate key of r. Maximum number of possible candidate keys of r is ________.
asked
in
Databases
Aug 9, 2022
673
views
made-easy-test-series
databases
candidate-key
0
votes
0
answers
4
Database: Minimum number of tuples
Consider a relation schema r(A, B, C). Number of elements in domain of attributes A, B and C are 4, 10 and 17 respectively. “ Minimum ” number of tuples possible in an instance of relation r is ________.
asked
in
Databases
Aug 9, 2022
303
views
databases
relations
1
vote
1
answer
5
Made easy || Operating system
Consider a process P running on a system with non-preemptive Kernel design. Consider following actions by P : (i) A blocking system call. (ii) Servicing a timer interrupt. (iii) Exit system call. (iv) Servicing a disk interrupt, that results in another blocked process being marked as ready. Which of the above actions always result in context-switch of P?
asked
in
Operating System
Aug 5, 2022
564
views
made-easy-test-series
operating-system
system-call
context-switch
0
votes
2
answers
6
Made easy || Operating system
While of the following is incorrect? (a) if a system uses preemptive CPU scheduler then deadlock is not possible in system (b) Deadlock state is an unsafe state. (c) If a system has total ordering of all resource types ... disabled) therefore deadlock should not possible in preemptive scheduling then how can this statement could be incorrect. please clarify the doubt
asked
in
Operating System
Aug 5, 2022
567
views
operating-system
made-easy-test-series
deadlock-prevention-avoidance-detection
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