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2
How to solve this recurrence relationT(n)= T(0.09n) + T(0.91n) + cnwhere c is constant and T(1)=1options are-
1 votes
1 answer
3
Consider a relation schema r(A, B, C, D, E, F) and attribute A is element of every candidate key of r. Maximum number of possible candidate keys of r is ________.
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4
Consider a relation schema r(A, B, C). Number of elements in domain of attributes A, B and C are 4, 10 and 17 respectively. “ Minimum ” number of tuples possible in a...