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Answers by Vikas123
0
votes
1
ME mock1
Consider a binary tree, where for every node P – Q ≤ 2, where P represents number of nodes in left sub tree for node S and Q represents the number of nodes in right sub tree for node S for h > 0. The minimum number of nodes present in such a binary tree of height h =4 will be 6 8 9 None of these
Consider a binary tree, where for every node P – Q ≤ 2, where P represents number of nodes in left sub tree for node S and Q represents the number of nodes in right s...
412
views
answered
Jan 19, 2019
DS
data-structures
binary-tree
numerical-answers
made-easy-test-series
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–
0
votes
2
UPPCL AE 2018:70
Consider the following grammar $\text{G:}$ $\text{P} \rightarrow \text{Q + R} \mid \text{Q - R} \mid \text{Q} \mid \text{R}$ $\text{Q} \rightarrow q \mid r$ $\text{R} \rightarrow r \mid s$ where $\text{P, Q,}$ and $\text{R}$ ... grammar $\text{G}$ Neither $\text{S1}$ nor $\text{S2}$ Only $\text{S1}$ Only $\text{S2}$ Both $\text{S1}$ and $\text{S2}$
Consider the following grammar $\text{G:}$$\text{P} \rightarrow \text{Q + R} \mid \text{Q – R} \mid \text{Q} \mid \text{R}$$\text{Q} \rightarrow q \mid r$$\text{R} \rig...
805
views
answered
Jan 13, 2019
Compiler Design
uppcl2018
compiler-design
parsing
ll-parser
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–
0
votes
3
made easy cbt1
FIFO replacement policy ignores locality of reference. true/false
FIFO replacement policy ignores locality of reference.true/false
1.2k
views
answered
Jan 13, 2019
Operating System
operating-system
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–
0
votes
4
ME Test
259
views
answered
Jan 13, 2019
0
votes
5
mad easy cbt 1
Let A be ternary tree with each node having 0 or 3 children . Let T have 25 node .The number of leaf nodes in ternary tree are
Let A be ternary tree with each node having 0 or 3 children . Let T have 25 node .The number of leaf nodes in ternary tree are
673
views
answered
Jan 13, 2019
0
votes
6
permutation and combination
1 2 10 16
121016
370
views
answered
Jan 13, 2019
0
votes
7
TLB hit ration and memory lookup time
Consider a system where TLB lookup time is $25$ ns and memory access time is $200$ ns, respectively. Assuming a virtual address space of $2$ KB, page size of $32$ bytes, and a PTE size of $2$ bytes, what is the minimum TLB hit ratio that results in an average v2p (virtual to physical) translation latency of $185$ ns?
Consider a system where TLB lookup time is $25$ ns and memory access time is $200$ ns, respectively. Assuming a virtual address space of $2$ KB, page size of $32$ bytes, ...
762
views
answered
Jan 13, 2019
Operating System
translation-lookaside-buffer
hit-ratio
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–
0
votes
8
me test series
A computer system implements a 38 bit virtual address, page size of 16 KB, and 256 entries translation look aside buffer (TLB) organized into 32 sets each having 8 ways. If TLB tag does not store any process id. The minimum length of TLB tag in bits is____
A computer system implements a 38 bit virtual address, page size of 16 KB, and 256 entries translation look aside buffer (TLB) organized into 32 sets each having 8 ways. ...
505
views
answered
Jan 11, 2019
Operating System
translation-lookaside-buffer
operating-system
+
–
0
votes
9
Madeeasy[CN-Flow control]
Consider two computers A and B are connected through a network of 30 Mbps.Assume the distance between them is 3000km and the signal propagation speed is same as the speed of light and the packet size is 12 KB. What is minimum number of bits required for window to achieve 100% utilization during GBN and SR protocol ?
Consider two computers A and B are connected through a network of 30 Mbps.Assume the distance between them is 3000km and the signal propagation speed is same as the speed...
1.2k
views
answered
Jan 10, 2019
Computer Networks
computer-networks
go-back-n
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–
0
votes
10
Made easy test series
266
views
answered
Jan 8, 2019
0
votes
11
DBMS transaction
Which of the following is used to get back all the transactions back after rollback? a)Rollback b)Commit c)undo d)Redo
Which of the following is used to get back all the transactions back after rollback?a)Rollbackb)Commitc)undo d)Redo
623
views
answered
Jan 8, 2019
Databases
databases
transaction-and-concurrency
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–
1
votes
12
MadeEasy Test Series 2019: Computer Networls - Congestion Control
Please help, I am getting total number of transmission to get BACK TO 38 as 14 and NOT 15. after 14th, it would have became 38, so no need to consider 15th segment right?
Please help, I am getting total number of transmission to get BACK TO 38 as 14 and NOT 15.after 14th, it would have became 38, so no need to consider 15th segment right?
975
views
answered
Jan 8, 2019
Computer Networks
computer-networks
congestion-control
made-easy-test-series
tcp
transport-layer
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–
2
votes
13
MadeEasy Test Series 2018: Compiler Design - Intermediate Code
The following program uses six temporary variables p, q, r, s, t and u. The code is : Assuming that all operations take their operands from registers. The minimum number of registers needed to execute this program without spilling are ... three lines and the last line are dead code. So the answer should be 2. Please correct me if wrong.
The following program uses six temporary variables p, q, r, s, t and u. The code is :Assuming that all operations take their operands from registers. The minimum number o...
1.4k
views
answered
Dec 24, 2018
Compiler Design
compiler-design
intermediate-code
made-easy-test-series
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–
0
votes
14
booth's multiplication algorithm
is booth's multiplication algorithm included in gate syllabus?
is booth's multiplication algorithm included in gate syllabus?
1.7k
views
answered
Dec 18, 2018
0
votes
15
ME TESTSERIES
If flooding is used to send packets from A to E, then the total number of packets generated in the above network when hop count for A to E is 3 are ________. ANSWER IS 14 .....BUT THE DOUBT IS THAT IS THEIR ANY EFFECT OF SAYING HOP COUNT FOR A TO E BECZ HERE IN 14 WE COUNTED THE HOP OF LENGTH...
If flooding is used to send packets from A to E, then the total number of packets generated in the above network when hop count for A to E is 3 are ________.ANSWER IS 14 ...
2.3k
views
answered
Dec 2, 2018
1
votes
16
GATE CSE 2003 | Question: 78
A processor uses $2-level$ page tables for virtual to physical address translation. Page tables for both levels are stored in the main memory. Virtual and physical addresses are both $32$ bits wide. The memory is byte addressable. For virtual to physical address translation, the ... virtual address is approximately (to the nearest $0.5$ ns) $1.5$ ns $2$ ns $3$ ns $4$ ns
A processor uses $2-level$ page tables for virtual to physical address translation. Page tables for both levels are stored in the main memory. Virtual and physical addres...
49.9k
views
answered
Aug 6, 2018
Operating System
gatecse-2003
operating-system
normal
virtual-memory
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