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Recent activity by himanshu6398
12
answers
1
GATE CSE 2009 | Question: 44
The following key values are inserted into a $B+$ - tree in which order of the internal nodes is $3$, and that of the leaf nodes is $2$, in the sequence given below. The order of internal nodes is the maximum number of tree pointers in each node, and the ... $1$ The maximum number of times leaf nodes would get split up as a result of these insertions is $2$ $3$ $4$ $5$
The following key values are inserted into a $B+$ - tree in which order of the internal nodes is $3$, and that of the leaf nodes is $2$, in the sequence given below. The ...
37.1k
views
commented
Nov 23, 2018
Databases
gatecse-2009
databases
b-tree
normal
+
–
10
answers
2
GATE CSE 1998 | Question: 27
Consider the following relational database schemes: COURSES (Cno, Name) PRE_REQ(Cno, Pre_Cno) COMPLETED (Student_no, Cno) COURSES gives the number and name of all the available courses. PRE_REQ gives the information about which courses are pre- ... relational algebra: List all the courses for which a student with Student_no 2310 has completed all the pre-requisites.
Consider the following relational database schemes:COURSES (Cno, Name)PRE_REQ(Cno, Pre_Cno)COMPLETED (Student_no, Cno)COURSES gives the number and name of all the availab...
8.2k
views
commented
Nov 17, 2018
Databases
gate1998
databases
relational-algebra
normal
descriptive
+
–
0
answers
3
nptel lecture on cpu scheduling
Why P1 is still running after 2ms, shouldn't P2 get the cpu burst? In the video they said that are are no processes present other than P1 when the timer interrupts after 2 time slices. Isn't the gantt chart wrong. What i am missing here, can anyone explain it right?
Why P1 is still running after 2ms, shouldn't P2 get the cpu burst? In the video they said that are are no processes present other than P1 when the timer interrupts after ...
771
views
commented
Oct 13, 2018
Operating System
round-robin-scheduling
+
–
1
answer
4
nptel lecture on stacks
While calculating the cost of growable array-based stack.... the cost of n pushes came out as a series - 2 + 4 + 8 + 16 +......+2^(logn + 1) and it equals to 4n - 1. I didn't understand how the series sum equals to 4n?
While calculating the cost of growable array-based stack.... the cost of n pushes came out as a series - 2 + 4 + 8 + 16 +......+2^(logn + 1) and it equals to 4n - 1. I di...
431
views
commented
Oct 9, 2018
DS
data-structures
stack
+
–
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