1 votes
4
1 votes
7
2 votes
11
Find the following sum.$$\frac{1}{2^{2}-1}+\frac{1}{4^{2}-1}+\frac{1}{6^{2}-1}+\cdots+\frac{1}{40^{2}-1}$$$\frac{20}{41}$$\frac{10}{41}$$\frac{10}{21}$$\frac{20}{21}$$1$
1 votes
15
2 votes
17
Let the representation of a number in base $3$ be $210$. What is the hexadecimal representation of the number?$15$$21$$\text{D}2$$528$
13 votes
25
28 votes
26