#include <stdio.h> #define A -B #define B -C #define C 5 int main(void) { printf("%d",A); return 0; } now my doubt here is, before compilaion i think macro will make printf part as, printf("%d",--5); which should give L-value error at compile time but, ... doing is printf("%d",-(-5)); leading to no compiler error and giving answer as 5, but macro implicitly never put precedence braces() itself...
asked
Nov 5, 2017
in Programming
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