Login
Register
Dark Mode
Brightness
Profile
Edit Profile
Messages
My favorites
My Updates
Logout
Filter
Profile
Wall
Recent activity
All questions
All answers
Exams Taken
All Blogs
Questions by ram_18051996
4
votes
1
answer
1
Relation and Partial order
Is (S, R) a poset if S is the set of all people in the world and (a, b) ∈ R, where a and b are people, if a is not taller than b?
Is (S, R) a poset if S is the set of all people in the world and (a, b) ∈ R, where a and b are people,if a is not taller than b?
2.6k
views
asked
Jul 7, 2017
Set Theory & Algebra
engineering-mathematics
relations
relational-algebra
partial-order
set-theory&algebra
+
–
2
votes
1
answer
2
Kenneth Rosen Edition 6th Exercise 7.5 Question 3 d (Page No. 507)
R is a relation on the set of all functions from Z to Z. R = { (f, g) | for some C ∈ Z , for all x ∈ Z , f(x) - g(x) = C } is it Equivalence relation or not ?
R is a relation on the set of all functions from Z to Z.R = { (f, g) | for some C ∈ Z , for all x ∈ Z , f(x) - g(x) = C } is it Equivalence relation or not ?
612
views
asked
Jul 5, 2017
Set Theory & Algebra
discrete-mathematics
relations
kenneth-rosen
set-theory&algebra
+
–
2
votes
1
answer
3
Set theory
{ a } ∈ A but a ∉ A why ? here ' a is the element of set {a} ' ,and ' set {a} is the element of A" , so " a also element of A " . please clear my doubt .
{ a } ∈ A buta ∉ Awhy ?here ' a is the element of set {a} ' ,and ' set {a} is the element of A" , so " a also element of A " . please clear my doubt .
546
views
asked
Jun 15, 2017
Set Theory & Algebra
set-theory&algebra
discrete-mathematics
engineering-mathematics
set-theory
+
–
3
votes
2
answers
4
FREE VARIABLE and VALIDITY related problem
Given that LHS : [(∃x,α(x))→β] RHS : [∃x,α(x)→β] Here α(x) is a first order formula with x as a free variable, and β is a first order formula with no free variable. than which one is valid ? a) LHS → RHS b) RHS → LHS
Given that LHS : [(∃x,α(x))→β]RHS : [∃x,α(x)→β]Here α(x) is a first order formula with x as a free variable, and β is a first order formula with no free v...
629
views
asked
Jun 12, 2017
Mathematical Logic
discrete-mathematics
mathematical-logic
kenneth-rosen
propositional-logic
+
–
1
votes
2
answers
5
# FREE VARIABLE ( NULL QUANTIFICATION ) Related problem
Given that LHS : [(∃x,α(x))→β] RHS : [∃x,α(x)→β] than which one is valid ? a) LHS → RHS b) RHS → LHS
Given that LHS : [(∃x,α(x))→β]RHS : [∃x,α(x)→β]than which one is valid ?a) LHS → RHSb) RHS → LHS
500
views
asked
Jun 12, 2017
Mathematical Logic
discrete-mathematics
mathematical-logic
propositional-logic
kenneth-rosen
+
–
0
votes
1
answer
6
This problem is related to Rule of inference and valid argument .
premises are - A A → ( B ∨ C ) B → ¬A conclusion - C is valid or not ?
premises are -AA → ( B ∨ C )B → ¬Aconclusion -C is valid or not ?
1.7k
views
asked
Jun 2, 2017
Mathematical Logic
mathematical-logic
discrete-mathematics
propositional-logic
+
–
Email or Username
Show
Hide
Password
I forgot my password
Remember
Log in
Register