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Questions by sid1221

1 votes
2 answers
1
Arun Sharma # progression
In an infinite geometric progression ,each term is equal to $2$ times the sum of the terms that follow . If the first term of the series is $8$ ,find the sum of the series?
In an infinite geometric progression ,each term is equal to $2$ times the sum of the terms that follow . If the first term of the series is $8$ ,find the sum of the serie...
2 votes
1 answer
2
floating point
If the decimal number is 3.248 * $10^{4}$then its 32 bit equivalent floating number is ?
If the decimal number is 3.248 * $10^{4}$then its 32 bit equivalent floating number is ?
0 votes
0 answers
3
compiler sdt
pls verify
pls verify
0 votes
1 answer
4
SDT (attribute )
pls explain c option
pls explain c option
0 votes
0 answers
5
synchronization
only 1st or 1st and 3rd statement is correct ? if i remove b then also i got mutual exclusion ..where am missing ?
only 1st or 1st and 3rd statement is correct ?if i remove b then also i got mutual exclusion ..where am missing ?
1 votes
0 answers
6
internal fragmentation
what will be ans ? in paging system ,page size = 2048B , A process might need 15 frames . what is the maximum possible internal fragmentation size ..?
what will be ans ?in paging system ,page size = 2048B , A process might need 15 frames . what is the maximum possible internal fragmentation size ..?
0 votes
1 answer
7
deadlock
is this correct
is this correct
0 votes
1 answer
8
function
2 votes
1 answer
9
combinatoric
No of ways to distribute 6 different gifts to 2 student from total 4 student ? my approach ... distinct to distinct ... am getting 378 , given ans is 384 ... they permuted ..is this correct ...?
No of ways to distribute 6 different gifts to 2 student from total 4 student ? my approach ... distinct to distinct ... am getting 378 , given ans is 384 ... they permute...
3 votes
1 answer
10
programming
a) 4 b)20 c)both d) either of them ... for me its 20 but given ans is either of them
a) 4 b)20 c)both d) either of them ... for me its 20 but given ans is either of them
2 votes
1 answer
11
C CODING
#include <stdio.h> int main() { float a=5.375; char *p; int i; p = (char*)&a; for(i=0; i<2; i++) printf("%x", (unsigned char)(p[i]^p[3-i])); return 0; } Explain in detail
#include <stdio.h int main(){ float a=5.375; char *p; int i; p = (char*)&a; for(i=0; i<2; i++) printf("%x", (unsigned char)(p[i]^p[3-i])); retur...
2 votes
1 answer
12
C CODING
#include <stdio.h> #include <stdlib.h> int* fun(); int main() { int *a = fun(); printf("%d",*a); return 0; } int* fun() { int *a =(int*) malloc(sizeof(int)); *a = 10; return a; } When it will give memory leak problem .. what should be changes ? pls explain in detail
#include <stdio.h #include <stdlib.h int* fun(); int main() { int *a = fun(); printf("%d",*a); return 0; } int* fun() { int *a =(int*) malloc(sizeof(int)); *a = 10; retur...
4 votes
1 answer
14
bitwise shift
#include <stdio.h> int main() { printf("%d", 1 << 2 + 3 << 4); return 0; } some one verify answer am getting 256 , given one 512 :(
#include <stdio.h int main() { printf("%d", 1 << 2 + 3 << 4); return 0; }some one verify answer am getting 256 , given one 512 :(
1 votes
1 answer
15
oprator
int main() { unsigned int x = 1; printf("Signed Result %d \n", ~x); printf("Unsigned Result %ud \n", ~x); return 0; } some one give detailed answer ... (mainly how it works )
int main(){unsigned int x = 1;printf("Signed Result %d \n", ~x);printf("Unsigned Result %ud \n", ~x);return 0;}some one give detailed answer ...(mainly how it works )
0 votes
1 answer
17
limit
solve following $\lim_{x->0} e^{ax}- e^{-ax}/ log(1+bx)$
solve following $\lim_{x->0} e^{ax}- e^{-ax}/ log(1+bx)$
2 votes
1 answer
20
EE,2016
Consider a $3\times 3$ matrix with every element being equal to 1 , its only non-zero eigenvalue is ....? $3\times 3 \begin{bmatrix} 1 & 1 &1 \\ 1 &1 &1 \\ 1 &1 &1 \end{bmatrix}$ ... but i got different eigen values why this happened ... i missed something ??
Consider a $3\times 3$ matrix with every element being equal to 1 , its only non-zero eigenvalue is ....?$3\times 3 \begin{bmatrix} 1 & 1 &1 \\ 1 &1 &1 \\ 1 &1 &1 \end{bm...
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