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GO Classes Weekly Quiz 9 | Data Structures | Linked List | Question: 11
A doubly linked list is declared as: struct Node { int Value; struct Node *prev; struct Node *next; }; Which of the following segment of code deletes the node pointed to by $\text{X}$ from the doubly linked list, if it is ... $; \text{X} \rightarrow$ next $\rightarrow$ prev $= \text{X} \rightarrow$ next; free(X);
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May 5, 2022
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GO Classes Weekly Quiz 9 | Data Structures | Linked List | Question: 8
If $f(n) = O(g(n))$ and $f(n) = \Omega(g(n)),$ then it is always true that $f(n) = o(g(n)).$ $f(n) = \theta(g(n)).$ $f(n) = \omega(g(n)).$ both A and B are always true.
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May 5, 2022
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1-mark
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GO Classes Weekly Quiz 9 | Data Structures | Linked List | Question: 12
Which of the following statement(s) is/are true? If $\text{T1}(x) = \text{O}(f(x))$ and $\text{T2}(x) = \text{O}(g(x))$ then $\text{T1}(x) + \text{T2}(x) = \text{O} (\max(f(x), g(x))$ If $\text{T}(x) = \text{O}(cf(x)),$ ... then $\text{T1}(x) \ast \text{T2}(x) = \text{O}(f(x) \ast g(x))$ $2^{(n+1)} = \text{O}(2^{n} ).$
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Programming
May 5, 2022
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4
GO Classes Weekly Quiz 9 | Data Structures | Linked List | Question: 6
Consider the following Doubly Linked List: If head points to the first node of the linked list then what will be the output of the following node? head=head->next->next->next->prev; head->next->next->prev=head; printf("%d",head->next->next->prev->next->value); $1$ $3$ $5$ $7$
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May 5, 2022
290
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goclasses_wq9
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2
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5
GO Classes 2023 | Weekly Quiz 8 | Question: 6
What will be the output of the following program? #include<stdio.h> struct _myst{ char b[20]; char *a; struct _myst *c; }x[2] = {"GATE", "Overflow", x+1, "GO", "Classes", x}, *p = x; typedef ... -1); } int main() { printf("%s",mystry(p,2023)->a); } GATE Overflow Run time error Compile-time error
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Apr 24, 2022
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6
GO Classes 2023 | Weekly Quiz 8 | Question: 2
Consider below four program fragments. Which of the program(s) is/are likely to produce run time error or memory leak. Assume malloc is always successful, and sizes are as follows - sizeof(int *) = 8 bytes sizeof(double) = 8 bytes sizeof(char) = 1 byte sizeof( ... ] = %d\n", a[0], a[1]); return 0; } Program $1$ Program $2$ Program $3$ Program $4$
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Apr 23, 2022
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