MadeEasy Subject Test: Compiler Design - Lexical Analysis

Question

Is the given answer correct?

Comments

it is 34
"printf("%d%d%d,a,b,c")" is 14 tokens

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21????

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I also write 21 but made easy people counted each token of that statement individually

I think their solution is wrong..!!

Answer 1

Total 34

"printf("%d%d%d,a,b,c")" 

will be considered as

"printf("      %      d         %         d        %          d      ,        a         ,        b       ,     c             ")"

NOT as 1 token but as 14 token

Comments

I got it.. It will work like this..For this statement "printf ( " is one token and at the end ")" is also a token...

total=34

Thanks..!!

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I didnt understood what are those 14 tokens can you specify???

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Tokens should be like this,

int main ( ) int a , b , c ; a + c ; etc. and i think "____" should be considered as one Token only!

So total should be 21

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exactly but someone here is saying "_________" it is 14 tokens

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@smartmeet u make it this ans wrong ?

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@bad_engineer @smartmeet

Initially i also counted as 21 but..

When lexical analyzer scans this statement it firstly see " and will map to the corressponding DFA or regular expression and will terminate when it reaches " and thus making " printf ( " as a token

Am i right ..??

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yes, I think you are right..it searches for next "

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@Ashwani Kumar

At first attempt i also got 21 ....so I thought over it... n got my mistake...

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yup me too understood my mistake

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what is the no. of token in following

printf("%d %d",a);

7 right

"printf("%d %d",a);"

no. of token is 9 right?

correct me if i am wrong

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akankshadewangan24  

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Where do u got that concept of 6 token?

Any reference?

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 srestha  may be i am wrong here but i think anything come between " " is a token.Please correct me i am wrong.

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yes, then how u divide  inside "...." and considered it separately?

Even in the selected ans of this question also considered 14 token, how?

Answer 2

Yes 34 is correct.

Comments

Thanku very much :)

Answer 3

Tokens:

1:: int  

2:: main 

3,4:: (  )

5,6::{ }

7::int

8,9,10:: a,a,a

11,12,13:: b,b,b

14,15,16::c,c,c 

17-24::=,,,,,;;;

25-30:: %%%ddd

31:: =

32:: +

33:: "printf("

34:: ")" 

Source: http://www.personal.kent.edu/~rmuhamma/Compilers/MyCompiler/chapter3.htm

Coreect me if I'm wrong!