GATE2016 CE-2: GA-10

Question

Ananth takes $6$ hours and Bharath takes $4$ hours to read a book. Both started reading copies of the book at the same time. After how many hours is the number of pages to be read by Ananth, twice that to be read by Bharath? Assume Ananth and Bharath read all the pages with constant pace.

• A. $1$
• B. $2$ 
• C. $3$ 
• D. $4$

Comments

Not getting answer bro,

here what I got

(I'm writing % of book read by both per hour)

A (6 hrs) : 16%  33%  50%  66%  83%  100%

B (4 hrs):  25%  50%  75%  100%  __    __

---

Hello smartmeet

You just got it , just you was not conscious.

See after 3rd hour Your A is done with half of the book(50% done naa)

and B is done with 3/4 of the book (75% done) so

A is left with 1/2 of the pages while B is left with 1/4 of the pages.See $\frac{1}{2}$ is double of $\frac{1}{4}$

Answer 1

following the approach of @Pascua but using LCM instead of fractions

Ananth takes 6 hours and Bharath takes 4 hours to read a book

the total work = lcm(6,4) = $24$ pages

In 1 hr A reads $4$ pages

In 1 hr B reads $6$ pages

In h hours A reads $4*h$ pages and  remaining pages he has to read is $24-(4*h)$

In h hours B reads $6*h$ pages and  remaining pages he has to read is $24-(6*h)$

 the number of pages to be read by Ananth, twice that to be read by Bharath

$24-(4*h) = 2 * (24 - (6 * h))$

$\therefore h=3$

Answer is Option $C$

Comments

@subbus yeah its a nice approach just a small typo in your answer lcm(6,4)=12 .

 

Answer 2

A-6hrs

B-4 hrs

so ration is 3:2

so 1.5:1(15*2:1*2)

so 3 is the answer