Inner for loop is dependent on $i$, so for each $i$ we have to check no of times inner loop operating..
It ll be something like
$\frac{n-1}{1}+\frac{n-1}{2}+\frac{n-1}{3}+...........+\frac{n-1}{n-1}+1$
$\frac{n}{1}+\frac{n}{2}+\frac{n}{3}+......+\frac{n}{n-1}-\log(n-1)$
$n\{{\frac{1}{1}+\frac{1}{2}+\frac{1}{3}+.....+\frac{1}{n-1}}\} - \log(n-1)$
$n\log(n-1)-\log(n-1)$
$n\log(n-1)$
$n\log n$
Correct Answer: $C$