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Let $S$ be a set of $n$ elements. The number of ordered pairs in the largest and the smallest equivalence relations on $S$ are:

  1. $n$ and $n$
  2. $n^2$ and $n$
  3. $n^2$ and $0$
  4. $n$ and $1$
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3 Answers

Best answer
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Answer is B.

Equivalence relation means it is reflexive, symmetric and transitive

If a relation is reflexive then it must have all the pairs of diagonal elements and relation with only diagonal elements is also symmetric and transitive. Therefore smallest such relation is of size $n.$

With diagonal elements, we can include all the elements as well.  Therefore largest equivalence relation is of size $n^2.$
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Smallest Equivalence relation on set S = ∆ ( Diagonal relation )

                                            Number of elements in  Diagonal relation = ∣S∣  = n  

                                           So, cardinality of Smallest Equivalence relation on set S  = n

 Note: Empty relation on Non-empty set will never be an equivalence relation because it does not satisfy the reflexive property.Whereas Empty relation on empty set will always be an equivalence relation.

Largest Equivalence relation on set S = S ⨉ S = ∣ S ⨉ S ∣ = n^2

                             So, cardinality of Largest Equivalence relation on set S  = n^2

The correct answer is, (B) n^2  and n
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Let S be a set of n elements say (1, 2, 3,... n).

Now the smallest equivalence relation on S must contain all the reflexive elements ((1, 1), (2, 2). (3, 3),..., (n, n)} and its cardinality is therefore n.

The largest equivalence relation on S is Sx S, which has cardinality of nxn = r².

 The largest and smallest equivalence relations on S have cardinalities of n² and n respectively.

Answer:

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