Declarartion

Question

Void fun(){

int i=0;

Printf("%d", i);

Static in j=12; // this is error to declare here right?????

J=j+1;

}

Comments

no, there will be no error, because when you write static int j=12; you are both declaring as well as defining a variable j. if you would have only written static int j;  then it would give semantic error because static int j; will only declare j but does not allocate memory for it.

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Nitish I am not getting what you want to say here,

yes program work fine here.

#include<stdio.h>
void main(){
int i=0;

printf("%d", i);
static int j= 10; // this is error to declare here right?????
j=j+1;
}

this is also fine :

#include<stdio.h>
void main(){
int i=0;

printf("%d", i);
static int j; // this is error to declare here right?????
j=j+1;
}​​​​​​​

this is also fine :

#include<stdio.h>
void main(){
int i=0;
static int j; // this is error to declare here right?????
j=j+1;

printf("%d", j);
}​​​​​​​

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i am highly sorry,

i misread the word static as extern, and then that word got stucked in my mind, and i answered it assuming that in the qsn it has given extern

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its ok 

but here i dont under stand the logic.

#include<stdio.h>
void main(){
int i=0;

printf("%d", j);
static int j; // this is error to declare here right?????
j=j+1;
}

why it gives error since static get memory at compile time and by default contain 0 also ans should be 0 but it gives error.

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because,

every variable should be declared before its usage, else it will give semantic error.

print(j) is used before declaration of static int j;

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static int j;  memory allocated at compile time isnt? compiler know about variable at compile time isnt?

if it was int j ; then i am ok that it will be semantic error.

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So this will give compile time error right??????