Answer : None of the options are correct ( Only statement 3 always correct )
Det ( M ) = 0 => Both columns & rows of square matrix M are Linearly Dependent.
Statement( 1 & 2 ) : A set of vectors are Linearly Dependent does’t mean that each one of them can be represented as linear combinations of other vectors. eg:
0 0 0
0 1 2
1 0 0 // This matrix obviously have determinant 0, so columns and rows are linearly dependent, but 3rd row ( 1 0 0 ) and first column ( [ 0 0 1 ]T ) cannot be represented as linear combinations of other rows/columns. So both S1 and S2 false.
Statement( 3 ) : This is correct, Ax = 0 will have a non trivial solution when the set of column vectors is Linearly dependent.
Statement( 4 ) : This is obviously false, A matrix have an inverse iff Det( M ) != 0